Given:
salary of 1,200 a month plus 3% of the sales price.
a) <span>The total of the sales prices of all the vehicles Sid sold during the first month on the job was $72000. What was Sid's income?
</span>72,000 x 3% = 2,160 commission
1,200 + 2,160 = 3,360
b) <span>In order to make $6000 in a single month, how much selling must Sid do?
</span>6,000 - 1,200 = 4,800
4,800 / 3% = 160,000 per month.
c) <span>Write a linear equation that expresses Sid's monthly income y in terms of the value x of the vehicles Sid sold
y = 1,200 + 3%x ; where x is the sales price of every vehicle sold.</span>
Answer: The value of the residual for advertising dollars spent equal to $1,020 and Profit equal to $17,500 is $417
Profit=372.6+17.2 (advertising dollars)
Advertising dollars=$1,020
Predicted Profit=372.6+17.2 (1,020)→
Predicted Profit=372.6+17,544→
Predicted Profit=$17,916.6
Residual=Predicted Profit-Profit→
Residual=$17,916.6-$17,500→
Residual=$416.6
Rounded to the nearest integer:
Residual=$417
Answer: The value of the residual for advertising dollars spent equal to $1,020 and Profit equal to $17,500 is $417
Answer:
the answer is b
Step-by-step explanation:
6 ft= 6x12in= 72 in.
8 ft= 8x12in= 96 in.
12ft=12x12in=144 in
25ft=25x12in=300 in
50ft=50x12in=600 in
72 in, 96 in, 96 in, 144 in, 300 in, 300 in, 600 in
Mean= (72+96+96+144+300+300+600)÷7
1608÷7 = 229.7 inches
Median=middle value in set = 144 inches
Mode= value(s) tha occur most often = 96 inches and 300 inches
Range=difference of largest and smallest values in set = 600-72= 528
Choice A
is the equivalent number of .