Answer:

Step-by-step explanation:
Given
Let

So:
--- probability of O
--- Number of spin
Using the complement rule, the probability that a spin will not land on orange is:


Express as decimal


On two spins, the probability that it will not land on orange is:

So, we have:


<em></em>
<em> --- approximated</em>
Answer:
chord CD is 11
Step-by-step explanation:
just add 2 and 9
Answer: 3.1 or 3.10
Step-by-step explanation:
3 and 10 hundredths = 3 + 10/100 = 3 + 0.10
3.10 / 3.1
Answer: 462
Step-by-step explanation:
943-481
Answer=462
U would factor by grouping and get x^2(x-2) + 3(x-2) and then get (x^2 +3) (x-2)