Simplify the expression (8x10^7)(2x10^6) write answer in scientific notation

Mathematics

1 answer:

lbvjy [14]3 years ago

8 0

2^4x^11000000 would be the answer in scientific notation.

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*WILL GIVEE BRAINLIEST FOR THE BEST ANSWER* Which of the following is NOT a biased sample?

Dafna1 [17]

Answer:

Step-by-step explanation:

All other options are more biased

In B, the official wants to use 50 people from a library to represent the <u>entire town's</u> opinion on the library itself.... that's biased.

In C, it's the same. Of course basketball players would like to watch basketball.... right?? That's why the choice is biased.

In D, the location is a deli.... and from experience people order meat at a deli... cuz why else go there?

8 0

2 years ago

boyakko [2]

Answer:

Example: these two triangles are similar: If two of their angles are equal, then the third angle must also be equal, because angles of a triangle always add to make 180°. So AA could also be called AAA (because when two angles are equal, all three angles must be equal)

5 0

2 years ago

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .