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DanielleElmas [232]
3 years ago
5

J. j. thomson is credited with which discoveries? select all that apply. subatomic particles neutrons isotopes electrons

Chemistry
2 answers:
Vsevolod [243]3 years ago
8 0
I believed he was credited with making, subatomic particles, isotopes and electrons. Joseph John Thomson was credited with the discovery and identification of the electron, and with the discovery of the first subatomic particle in 1897. He also discovered isotopes, and invented a mass spectrometer and was awarded the Nobel Prize in physics in 1906. 
-Dominant- [34]3 years ago
7 0

Answer:

electrons

Explanation:

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How many grams are in 2.5 moles of Carbon
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According to the periodic table, carbon's molar mass is 12.011 grams per mole (that's the small number under the element).  So, just multiply like this to get the answer:

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3 years ago
Read 2 more answers
Pentaborane-9,
frozen [14]

Given question is incomplete. The complete question is as follows.

Pentaborane (B_{5}H_{9}) is a colorless highly reactive liquid that will burst into flames when exposed to oxygen.the reaction is:

  2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)

Calculate the kilojoules of heat released per gram of the compound reacted with oxygen.the standard enthalpy of formation B_{5}H_{9}(l) , B_{2}O_{3}(s), and H_{2}O(l) are 73.2, -1271.94, and -285.83 kJ/mol, respectively.

Explanation:

As the given reaction is as follows.

   2B_{5}H_{9}(l) + 12O_{2} \rightarrow 5B_{2}O_{2}(s) + 9H_{2}O(l)

Therefore, formula to calculate the heat energy released is as follows.

       \Delta H = \sum H_{products} - \Delta H_{reactants}

Hence, putting the given values into the above formula is as follows.

         \Delta H = \sum H_{products} - \Delta H_{reactants}

     = 5 \times (-1271.94 kJ/mol) + 9 \times (-285.83 kJ/mol) - 2 \times (73.2 kJ/mol) - 12(0)

     = -9078.59 kJ/mol

Since, 2 moles of Pentaborane reacts with oxygen. Therefore, heat of reaction for 2 moles of Pentaborane is calculated as follows.

        \frac{\Delta H}{2 \times \text{molar mass of pentaborane}}      

         \frac{-9078.59 kJ/mol}{2 \times 63.12 g/mol}

                  = -71.915 kJ/g

Thus, we can conclude that heat released per gram of  the compound reacted with oxygen is 71.915 kJ/g.

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