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leva [86]
3 years ago
8

How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?

Chemistry
1 answer:
yuradex [85]3 years ago
4 0

Answer:

63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid

I'm sorry if it's wrong, I tried.

Explanation:

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4. How many milligrams are in 5.25 x 10-13 kg?<br><br> the “-13” is an exponent
rusak2 [61]

5. 25 x 10⁻⁷mg

Explanation:

This is mass conversion from mg to kg;

The kg is a quantity of mass used to measure the amount of matter in a substance.

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The kilo-  is a prefix that denotes 10³

  therefore;

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 the milli-  is a prefix that denotes 10⁻⁻³

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Now that we know this, we can convert:

   5.25 x 10⁻¹³kg  x \frac{1000g}{1kg}  x \frac{1000mg}{1g}   =  5. 25 x 10⁻¹³ x 10⁶mg

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learn more:

Conversion brainly.com/question/1548911

#learnwithBrainly

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