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leva [86]
3 years ago
8

How many grams of aluminum is required to react with 75.0 ml of 2.50 M HCl?

Chemistry
1 answer:
yuradex [85]3 years ago
4 0

Answer:

63 g Al is required to react with 35 mL of 2.50 M hydrochloric acid

I'm sorry if it's wrong, I tried.

Explanation:

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How would you balance the following equation NaOh + H2CO3=Na2CO3+H2O ?
mamaluj [8]

Answer: put 2 in front of NaOH and 2 also in front of H2O

Explanation: 2NaOH + H2CO3 —> Na2CO3 + 2H2O

8 0
4 years ago
The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appear
djverab [1.8K]

Answer: The rate of appearance of Br_2 is 0.0700Ms^{-1}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br(g)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of HBr = -\frac{1d[HBr]}{2dt}Rate in terms of appearance of [tex]H_2 = \frac{1d[H_2]}{dt}

Rate in terms of appearance of Br_2 = \frac{1d[Br_2]}{dt}

-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}

Given :

-\frac{1d[HBr]}{dt}=0.140Ms^{-1}

The rate of appearance of Br_2;

\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}

Thus rate of appearance of Br_2 is 0.0700Ms^{-1}

6 0
3 years ago
How do electrons differ from protons and neutrons? A. They do not move. B. They are larger. C. They are not in a fixed position.
nikdorinn [45]
Hi!

Electrons are particles which basically 'orbit' around the nucleus. Protons and neutrons are condensed, in a fixed position inside the nucleus. 

With this in mind, the answer will be C.

Hopefully, this helps! =)
4 0
4 years ago
Read 2 more answers
Consider the following equation: K + Br → KBr. How many grams of KBr can you make with 1.25g of K?
Dmitry [639]

Answer:

\fbox{3.81 \: grams}

Explanation:

First consider the mol to mol ratio, the mol of a substance is simply the count of atoms in respect to avagadros number (approx. 6.02 × 10²³ molecules) in the period table. 1 mol of an element is simply it's mass count in the periodic table.

5 0
3 years ago
6. How is energy transferred to the earth?I
qaws [65]

Answer:

Energy is transferred between the earths surface and atmosphere.Energy move place to place

8 0
3 years ago
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