The abbreviation Al, with one dot on top of the abbreviation, one on the left, one on the right.
Answer:
See Explanation
Explanation:
The question is incomplete; as the mixtures are not given.
However, I'll give a general explanation on how to go about it and I'll also give an example.
The percentage of a component in a mixture is calculated as:

Where
E = Amount of element/component
T = Amount of all elements/components
Take for instance:
In 
The amount of all elements is: (i.e formula mass of
)



The amount of calcium is: (i.e formula mass of calcium)



So, the percentage component of calcium is:




The amount of hydrogen is:



So, the percentage component of hydrogen is:




Similarly, for oxygen:
The amount of oxygen is:



So, the percentage component of oxygen is:




WHAT THE HECK!?!?!?! AM I SUPPOSE TO KNOW WHATEVER LANGUAGE THAT IS?!?!
Answer:
Your question seems to me that it is somewhat poorly written, but it could help you by telling you that by increasing the collision of the individuals, the friction between them increases, therefore increasing the release of energy in the form of heat and thus increasing the temperature.
Therefore, the hypothesis raised would be correct.
Explanation:
If the shock is perfectly inelastic (plastic), the kinetic energy is not conserved and, as a consequence, the colliding bodies can undergo deformations and increase in temperature.