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Papessa [141]
3 years ago
6

Someone please help!!

Chemistry
1 answer:
Y_Kistochka [10]3 years ago
5 0
Since density is mass in grams divided by volume in liters, you first have to convert mL to L then solve

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Can someone please helpppp!
dolphi86 [110]

Answer: A

Aloha is the one that loses a helium

5 0
3 years ago
Given the equation representing a reversible reaction:which formula represents the h+ acceptor in the forward reaction?
AnnyKZ [126]
Question is incomplete. Complete question is attached below
.............................................................................................................................

Answer: Option A: HCO3-(aq.)

Reason:
From the reaction, it can be seen that following reaction occurs in forward direct

HCO3-(aq)     +     H2O(l)      →      H2CO3(aq)     +      OH-(aq)

In above forward reaction, HCO3- accepts proton from H2O to generate H2CO3. Thus, according to Lowry and Bronsted theory of acid-base, HCO3- is a base, while H2CO3 is a conjugate acid. 

8 0
3 years ago
Use the IUPAC nomenclature rules to give the name for Mg(ClO4)2
Makovka662 [10]

Answer:

The answer to your question is Magnesium Perchlorate

Explanation:

IUPAC Rules to name ternary salts of chlorine

1.- Ternary salts use prefixes and suffixes it depends on the number of oxygens they have.

Example

Metal + Chlorine + 1 oxygen =  Name of the metal + hipo chlor + ite

Metal + Chlorine + 2 oxygens = Name of the metal + chlor + ite

Metal + Chlorine + 3 oxygens = Name of the metal + chlor + ate

Metal + Chlorine + 4 oxygens = Name of the metal + per + chlor + ate

For this compound the name is  Magnesium Perchlorate.

6 0
3 years ago
How much heat must your body transfer to 500.0g of water to heat it from 25.0°C to body temperature, 37.0°C?
shtirl [24]

Answer : The heat your body transfer must be, 25.1 kJ

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat = ?

m = mass of water = 500.0 g

c = specific heat of water = 4.18J/g^oC

T_1 = initial temperature  = 25.0^oC

T_2 = final temperature  = 37.0^oC

Now put all the given value in the above formula, we get:

Q=500.0g\times 4.18J/g^oC\times (37.0-25.0)K

Q=25080J=25.1kJ

Therefore, the heat your body transfer must be, 25.1 kJ

3 0
3 years ago
_NaHCO(s) --&gt; _CO2+_NaCO(s)+_H2O<br><br>balance the equation​
elena55 [62]

The balanced equation :

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

<h3>Further explanation</h3>

Given

Reaction

NaHCO(s) --> _CO2+_NaCO(s)+_H2O

Required

The balanced equation

Solution

Maybe the equation should be like this :

NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

Give a coefficient

NaHCO₃⇒aCO₂ + bNa₂CO₃+cH₂O

Make an equation

Na, left=1, right=2b⇒2b=1⇒b=1/2

H, left=1, right=2c⇒2c=1⇒c=1/2

C, left=1, right=a+b⇒a+b=1⇒a+1/2=1⇒a=1/2

The equation becomes :

NaHCO₃⇒1/2CO₂ +1/2Na₂CO₃+1/2H₂O x2

2NaHCO₃⇒CO₂ + Na₂CO₃+H₂O

5 0
3 years ago
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