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pentagon [3]
3 years ago
10

Consider the chemical equation.

Chemistry
2 answers:
frez [133]3 years ago
8 0

NBr₃ is the answer young man.

likoan [24]3 years ago
5 0
NBr₃ : NaOH = 2 : 3
40    :    48    = 2 : 2.4
40    :    48    = 2.5 : 3

NBr₃ is the excess reactant
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What factors affect the geometry of a molecule?
natali 33 [55]

The factors that affect geometry of a molecule are

> The number of bonding electron pairs around the central atom.

> The number of pairs of non-bonding ("lone pair") electrons around the central atom.

4 0
3 years ago
How to convert 12g of H2O to moles
Anna35 [415]

Answer:

moles = given mass/atomic mass

so H2O mass = 2 +16=18

so 12g of h2o= 12/16 = 3/4 moles

8 0
2 years ago
A solution is prepared by dissolving 15.0 g of nh3 in 250.0 g of water. the density of the resulting solution is 0.974 g/ml. the
sergeinik [125]
The formula for molality---> m = moles solute/ Kg of solvent

the solute here is NH₃ because it's the one with less amount. which makes water the solvent.

1) let's convert the grams of NH₃ to moles using the molar mass

molar mass of NH₃= 14.0 + (3 x 1.01)= 17.03 g/ mol

15.0 g (1 mol/ 17.03 g)= 0.881 mol NH₃

2) let's convert the grams of water into kilograms (just divide by 1000)

250.0 g= 0.2500 kg

3) let's plug in the values into the molality formula

molality= mol/ Kg---> 0.881 mol/ 0.2500 kg= 3.52 m
6 0
3 years ago
Determine the electron geometry (eg) and molecular geometry (mg) of CO2.
eimsori [14]

Answer:

eg=linear, mg=linear

Explanation:

First of all, it must be stated that most triatomic molecules are either linear or bent. This depends on the electron geometry of the molecule and the number of bonding groups, multiple bonds and lone pairs present.

CO2 contains four regions of electron density and two bonding groups. For a specie containing two bonding groups, a linear molecular geometry is expected with an angle of 180°.

For a specie having two bonding groups and no lone pairs with multiple bonds, the expected electron geometry is also linear.

6 0
4 years ago
The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. what is this distance in cen
e-lub [12.9K]
<span>pm stands for picometer and picometers are units which can be used to measure really tiny distances. One picometer is equal to 10^{-12} meters. We know that one centimeter is equal to 10^{-2} m so there are 10^2 cm per meter. We can change the distance d = 115 pm to units of centimeters. d = (115 pm) x (10^{-12}m / pm) x (10^2 cm / m) d = 115 x 10^{-10} cm = 1.15 x 10^{-8} cm The distance in centimeters is 1.15 x 10^{-8} cm</span>
7 0
3 years ago
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