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umka21 [38]
2 years ago
8

Calculate the number of grams of aluminum chloride produced when 8.6 moles of aluminum react with chlorine gas.

Chemistry
1 answer:
Ratling [72]2 years ago
6 0

Answer:

1148 grams

Explanation:

The balanced chemical reaction of this question is as follows:

2Al + 3Cl2 → 2AlCl3

Based on the equation above;

2 moles of Aluminum react to produce 2 moles of Aluminum chloride (AlCl3)

Therefore, 8.6 moles of aluminum will react to produce: 8.6 × 2/2

= 8.6moles of AlCl3.

Using mole = mass ÷ molar mass, to determine the number of grams.

Molar Mass of AlCl3 = 27 + 35.5(3)

= 27 + 106.5

= 133.5g/mol

Using mole = mass/molar mass

Mass = molar mass × mole

Mass = 133.5 × 8.6

Mass = 1148.1

Mass of AlCl3 = 1148 grams

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A sample of seawater consists of water, sodium ions, chloride ions, and several other dissolved salts. These ions and salts are
stellarik [79]

Answer:

Mixture, homogeneous mixture, solution

Explanation:

A mixture is defined as a substance which is made by physical combination of two or more substance.

As in sea water, more than two substance are present, therefore is considered as mixture.

A mixture is considered as homogeneous mixture, if it has same proportion of components through out the mixture. In sea water proportions of all the components are same, therefore, its is also a homogeneous mixture.

In solution, solute is dissolved in a solvent and the concentration of the solute is same through out the solution.. In sea water, sodium ions, chloride ions, and several other salts are dissolved in water. Therefore, water is considered as solvents and components present are considered as solute.

so, sea water can also considered as solution.

Among the given options, 1, 3 and 4 are correct

So, sea water is considered as mixture, homogeneous mixture and solution.

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3 years ago
Determine the number of equivalents if a 3.89N solution contains 0.76 L of solution
ValentinkaMS [17]

Answer:

2%

Explanation:

oriented C-2, and (3) the minimizing of the number of ... (2) L. A. Mitscher, J. K. Paul, and L. Goldman,Experientia, 19, 195. (1963). ... SOzCeHiBr)3 in 147 ml. of anhydrous methanol containing 0.37 ... bicarbonate and saturated sodium chloride solution, and dried ... determined in 2% chloroform solution; infrared spectra on.

5 0
3 years ago
What evidence supports the law of conservation of energy?
Travka [436]

Answer:

light energy is converted to chemical energy during photosynthesis.

Explanation:

Law of conservation of energy says: Energy can neither be created nor destroyed-only converted from one form of energy to another.

3 0
2 years ago
Сульфат железа (II) окисляется в кислой среде перманганатом калия до Fe2(SO4)3, т.е. окисляется. Запишите и приравняйте уравнени
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3 years ago
What is the freezing point (in degrees Celcius) of 4.14 kg of water if it contains 235.1 g of butanol, C 4 H 9 O H
Karolina [17]

Answer:

Explanation:

Molal freezing point depression constant of butanol Kf = 8.37⁰C /m

ΔTf = Kf x m , m is no of moles of solute per kg of solvent .

mol weight of butanol = 70 g

235.1 g of butanol = 235.1 / 70 = 3.3585 moles

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= 6.79⁰C

Depression in freezing point = 6.79

freezing point of solution = - 6.79⁰C .

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2 years ago
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