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2 years ago

What type of particle is emitted by each type of radioactive decay?

Chemistry

2 answers:

Natasha_Volkova [10]2 years ago

5 0

Answer : The correct option is, (C) alpha = nucleus of a helium atom, beta = electron, gamma = photon

Explanation :

Alpha particle : It is also known as alpha radiation or alpha ray that consists of 2 protons and 2 neutrons that are bound together into a particle that is identical to the helium nucleus. It is produced in the process of alpha decay.

Beta particle : It is also known as beta radiation or beta ray. During the beta decay process, a high energy and speed electron or positron are emitted by the radioactive decay of atomic nucleus.

Gamma particle : It is also a gamma radiation or gamma ray that is arising from the radioactive decay of atomic nuclei. It has shortest wavelength waves and imparts high photon energy can pass through most forms of matters because they have no mass.

Hence, the correct option is, (C) alpha = nucleus of a helium atom, beta = electron, gamma = photon

olya-2409 [2.1K]2 years ago

4 0

C. alpha = nucleus of a helium atom

beta = electron

gamma = photon

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Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu

borishaifa [10]

Answer:

$\large \boxed{\mathbf{1.36; 3.6 \times 10^{\mathbf{-9}}}\textbf{mol/L}}$

Explanation:

The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.

1 .Calculate the hydronium ion concentration

We can use an ICE table to organize the calculations.

HF + H₂O ⇌ H₃O⁺ + F⁻

I/mol·L⁻¹: 2.7 0 0

C/mol·L⁻¹: -x +x +x

E/mol·L⁻¹: 2.7 - x x x

$K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}] \text{F}^{-}]} {\text{[HF]}} = 7.2 \times 10^{-4}\\\\\dfrac{x^{2}}{2.7 - x} = 7.2 \times 10^{-4}\\\\\text{Check for negligibility of }x\\\\\dfrac{2.7}{7.2 \times 10^{-4}} = 4000 > 400\\\\\therefore x \ll 2.7\\\dfrac{x^{2}}{2.7} = 7.2 \times 10^{-4}\\\\x^{2} = 2.7 \times 7.2 \times 10^{-4} = 1.94 \times 10^{-3}\\x = 0.0441\\\text{[H$_{3}$O$^{+}$]}= \text{x mol$\cdot$L$^{-1}$} = \text{0.0441 mol$\cdot$L$^{-1}$}$

2. Calculate the pH

$\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{0.0441} = \large \boxed{\mathbf{1.36}}$

3. Calculate [C₆H₅O⁻]

C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺

2.7 x 0.0441

$K_{\text{a}} = \dfrac{0.0441x} {2.7} = 1.6 \times 10^{-10}\\\\0.0441x = 1.6 \times 10^{-10}\\x = \dfrac{1.6 \times 10^{-10}}{0.0441} = \mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}\\\text{The concentration of phenoxide ion is $\large \boxed{\mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}}$}$

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3 years ago

Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equ

DedPeter [7]

Answer:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

Explanation:

Solid Iron = Fe

Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).

Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)

Metal Copper = Cu

Writing the equation using symbols leaves us with:

Fe + CuNO₃ → Fe(NO₃)₃ + Cu

It is not balanced yet. Now we balance the NO₃ species on the left side:

Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu

Finally we balance the Cu species on the right side:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

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2 years ago

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liberstina [14]

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Explanation:

this is the answer please mark me as brainleist

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Explanation:

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