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Dimas [21]
3 years ago
12

What type of particle is emitted by each type of radioactive decay?

Chemistry
2 answers:
Natasha_Volkova [10]3 years ago
5 0

Answer : The correct option is, (C) alpha = nucleus of a helium atom, beta = electron,  gamma = photon

Explanation :

Alpha particle : It is also known as alpha radiation or alpha ray that consists of 2 protons and 2 neutrons that are bound together into a particle that is identical to the helium nucleus. It is produced in the process of alpha decay.

Beta particle : It is also known as beta radiation or beta ray. During the beta decay process, a high energy and speed electron or positron are emitted by the radioactive decay of atomic nucleus.

Gamma particle : It is also a gamma radiation or gamma ray that is arising from the radioactive decay of atomic nuclei. It has shortest wavelength waves and imparts high photon energy can pass through most forms of matters because they have no mass.

Hence, the correct option is, (C) alpha = nucleus of a helium atom, beta = electron,  gamma = photon

olya-2409 [2.1K]3 years ago
4 0

C. alpha = nucleus of a helium atom

beta = electron

gamma = photon

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The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and
zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

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The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

z = \dfrac{x - \mu }{\sigma }

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z = \dfrac{11.5 - 13.9 }{5.8 } =  \dfrac{-2.4 }{5.8 } = 0.4138

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

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We have;

z = \dfrac{14- 13.9 }{5.8 } =  \dfrac{0.1}{5.8 } = 0.01724

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, p_{ca}, that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

p_{ca} = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

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Multiply 'til whole

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Divide by the smallest mole
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Multiply to make whole number ( x3 in this case)
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