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3 years ago

A taxi cab driver charges a $2.00 initial fee and $1.75 for each mile.

2 answers:

7 0

1. She can travel 18 miles. Subtract 35 - 2 (initial fee) to have 33. divide 33 by 1.75 to get 18.85. To check how much her total would be, use inverse operations. 18.85 * 1.75 = 32.9875. 32.9875 + 2 = 34.9875. It is barely under $35 but still in her budget.

2. 20m * $1.75 = $35. $70 - $35 = $35. Yes, she can cover the fare. Samantha has more than needed. She can afford the taxi fare and still have money left for future use.

Pepsi [2]3 years ago

3 0

Answer:

Step-by-step explanation:

1) Shannon can travel exactly 18 miles.

2) Yes, Samantha has enough money for her taxi. The ride would cost her $37. She would have $33 left over.

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Is x a solution to 80<-9x+8

saveliy_v [14]

Answers: $x$

1. Switch sides

$-9x+8>80$

2. Subtract by 8 from both sides of equation.

$-9x+8-8>80-8$

3. Simplify.

$-9x>72$

4. Multiply by -1 from both sides of equation. (it's should be the reverse inequality).

$(-9x)(-1)$

5. Simplify.

$9x$

6. Then you had to divide by 9 from both sides of equation.

$\frac{9x}{9}< \frac{-72}{9}$

7. Simplify.

$\frac{9x}{9}=x$

8. Divide by the numbers.

$\frac{9}{9}=1$

$=x$

$\frac{-72}{9}=-8$

9. Divide by the numbers.

$\frac{72}{9}=8$

$=-8$

$x$

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3 0

3 years ago

Solve f(2) for f(x)=x-51<br><br> f(2)= [?]

givi [52]

Plug in 2 for x. f(20=2-51 = -49

5 0

3 years ago

Read 2 more answers

Helpppp meeeee outttttt pleaseeeee ASAPPPP!!!!

Ilya [14]

Answer:

$\boxed{\sf sin\ C =\frac{40}{41}}$

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

$\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}$

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

$\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}$