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Vesnalui [34]
3 years ago
8

Suppose u and v are differentiable functions of x and that

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

B I personally think..

Step-by-step explanation:

Hi,

Use Differential Formula :

d(u(x) • v(x))/dx = u'(x) • v(x) + u(x) • v'(x)

at x = 1 :

d(u(1) • v(1))/dx = u'(1) • v(1) + u(1) • v'(1)

d(u(1) • v(1))/dx = -5 • 6 + 4  • -2

d(u(1) • v(1))/dx = -30 - 8

d(u(1) • v(1))/dx = -38

Hope this helped :)

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Answer:

Step-by-step explanation:

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3 years ago
After the 30% discount was applied, Patricia paid $45.50 for the ring. What was the original price of the ring
romanna [79]
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3 years ago
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zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

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Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

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ANTONII [103]

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