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Vesnalui [34]
3 years ago
8

Suppose u and v are differentiable functions of x and that

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

B I personally think..

Step-by-step explanation:

Hi,

Use Differential Formula :

d(u(x) • v(x))/dx = u'(x) • v(x) + u(x) • v'(x)

at x = 1 :

d(u(1) • v(1))/dx = u'(1) • v(1) + u(1) • v'(1)

d(u(1) • v(1))/dx = -5 • 6 + 4  • -2

d(u(1) • v(1))/dx = -30 - 8

d(u(1) • v(1))/dx = -38

Hope this helped :)

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What is 14 pints equal to in cups?
lilavasa [31]
There are 2 cups in 1 pint. So you could count by 2s until you get to 14. Or you can multiply 14×2=28
4 0
3 years ago
Find the value of x.<br> 1680<br> x = [? ]°
lapo4ka [179]
Please mark brainliest

x= 192

Explanation: the circle is 360 in total so subtract 168 from 360
4 0
3 years ago
What is the domain and range of the relation shown in
Leya [2.2K]

Answer:

Domain : {10, 15, 19, 32}

Range: {-1, 5, 9}

Step-by-step explanation:

As the table of the relation is given as follows:

<em>X                Y</em>

<em>10               5</em>

<em>15               9</em>

<em>19               -1</em>

<em>32             5  </em>

From this table, we can define the relation by combining the ordered pairs from the table. Each and every order pair consists of x-coordinate and corresponding y-coordinate of any corresponding point.

So, the relation from the table can be made as follows:

                            relation : {(10, 5), (15, 9), (19, -1), (32, 5)}

Domain of a relation consists of all the x-coordinates (first elements) of order pairs.

Range of a relation consists of all the y-coordinates (second elements) of ordered pairs.

So, domain  and range of relation will be as follows:

                                  Domain : {10, 15, 19, 32}

                                  Range: {-1, 5, 9}

<em>Note: If there is any </em><em>duplicate</em><em> element in any x or y-coordinate of any ordered pair, it will be written only </em><em>once </em><em>when we determine domain and range. Here, in this example, 5 is duplicate, so, it will be mentioned only one time when we determine the range of this relation.</em>

Keywords:  domain, relation, range

Learn more about domain and range of a relation from brainly.com/question/11422136

#learnwithBrainly

6 0
3 years ago
Calculate the surface area of an open cuboid which is 12 cm long,8cm wide,6cm high​
Vsevolod [243]

Answer:

432 cm²

Step-by-step explanation:

To find the surface area of a cuboid, there is a formula.

2lw+2lh+2hw

Length is l, height is h, and width is w.

2(12)(8)+2(12)(6)+2(6)(8)

Multiply all the terms.

336+96

Add both the terms.

= 432

The surface area of the open cuboid is 432cm².

6 0
3 years ago
Read 2 more answers
Is a triangle with sides of length 6ft, 21 ft, 23 ft. A right triangle?
gayaneshka [121]

Answer:

No

Step-by-step explanation:

By using the Pythagoras theorem, it can be easily determined that whether the triangle is right triangle or not.

Thus, a^{2}+b^{2}=c^{2} where where a and b are the legs and c is the hypotenuse.

Let a=6ft, b=21ft and c=23ft, then

a^{2}+b^{2}=c^{2}

(6)^{2}+(21)^{2}=(23)^{2}

36+441=(23)^{2}

477=529

which is not possible, therefore the given triangle is not right triangle because it does not satisfy the Pythagoras theorem.


7 0
3 years ago
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