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Aliun [14]
4 years ago
8

What is the relation between an equation and experiment.?

Chemistry
1 answer:
Snowcat [4.5K]4 years ago
5 0

Explanation:

An equation is a symbolic representation of a chemical reaction but in the form of symbols. And a experiment is when the teacher stand infront of you and shows you exactly what happens, the eqaution is to underdstand which elements are reacting to what.

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The part of earth system that contains all of earths water is called
vlabodo [156]
I think the answer is hydrosphere
7 0
3 years ago
Read 2 more answers
Three moles of an ideal gas undergo a reversible isothermal compression at temperature 18.0 ?c. during this compression, an amou
Lena [83]
We calculate the entropy of an ideal gas follows:

<span>For an isothermal compression, change in internal energy is equal to zero.</span>
<span>Thus, the heat added to the gas is equal to the work done on the gas which is given as 1750 J.</span>

<span>Entropy would be 1750/301 = 5.81 J/K </span>
3 0
3 years ago
How much energy is required to heat 87.1 g acetone (molar mass=58.08 g/mol) from a solid at -154.0°C to a liquid at -42.0°C? The
WARRIOR [948]

Answer:

The answer to the question above is

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C = 29.36 kJ

Explanation:

The given variables are

ΔHfus = 7.27 kJ/mol

Cliq = 2.16 J/g°C

Cgas = 1.29 J/g°C

Csol = 1.65 J/g°C

Tmelting = -95.0°C.

Initial temperature = -154.0°C

Final temperature = -42.0°C?

Mass of acetone = 87.1 g

Molar mass of acetone = 58.08 g/mol

Solution

Heat required to raise the temperature of solid acetone from -154 °C to -95 °C or 59 °C is given by

H = mCsolT = 87.1 g* 1.65 J/g°C* 59 °C = 8479.185 J

Heat required to melt the acetone at -95 °C = ΔHfus*number of moles =

But number of moles = mass÷(molar mass) = 87.1÷58.08 = 1.5

Heat required to melt the acetone at -95 °C =1.5 moles*7.27 kJ/mol = 10.905 kJ

The heat required to raise the temperature to -42 degrees is

H = m*Cliq*T = 87.1 g* 2.16 J/g°C * 53 °C = 9971.21 J

Total heat = 9971.21 J + 10.905 kJ + 8479.185 J = 29355.393 J = 29.36 kJ

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C is 29.36 kJ

4 0
4 years ago
2. In contrast to Venus, the coldest temperature yet measured on the surface of
Leviafan [203]

38K

-391°F

Explanation:

Given temperature:

Temperature of Triton = -235°C

Unknown:

Surface temperature of Triton in °F and Kelvin

Solution:

Temperature is the degree of hotness or coldness of a body.

It is usually measured using units of kelvin, degree Celsius and degree Fahrenheit.

tK = 273 + t°C    from °C  to K

t°F = \frac{9}{5} t°C  + 32

 

tk = temperature in kelvin

 t°C = temperature in Celsius

t°F = temperature in Fahrenheit

tK = 273 + (-235) = 38K

t°F = \frac{9}{5} x (-235)   + 32  = -423 + 32 = -391°F

learn more:

Heat and temperature brainly.com/question/914750

#learnwithBrainly

7 0
4 years ago
Potassium carbonate, K2CO3, sodium iodide, NaI, potassium bromide, KBr, methanol, CH3OH, and ammonium chloride, NH4Cl, are solub
just olya [345]

Answer:

A. K₂CO₃

Explanation:

The chemical reaction showing the ions produced on dissolving Potassium carbonate in water is:

K₂CO₃ ⇒ 2K⁺ + CO₃²⁻

Number of ions produced = 2 + 1 = 3

The chemical reaction showing the ions produced on dissolving sodium iodide in water is:

NaI ⇒ Na⁺ + I⁻

Number of ions produced = 1 + 1 = 2

The chemical reaction showing the ions produced on dissolving potassium bromide in water is:

KBr ⇒ K⁺ + Br⁻

Number of ions produced = 1 + 1 = 2

The chemical reaction showing the ions produced on dissolving ammonium chloride in water is:

NH₄Cl ⇒ NH₄⁺ + Cl⁻

Number of ions produced = 1 + 1 = 2

<u>The largest number of dissolved particles per mole of dissolved solute is produced by Potassium carbonate.</u>

5 0
4 years ago
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