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2 years ago

Pacing thresholds of temporary epicardial electrodes: Variation with electrode type, time, and epicardial position

1 answer:

Rudiy272 years ago

7 0

Pacing thresholds of temporary epicardial electrodes: Variation with electrode type of anxiety (low vs. high) and stress.

Everyone experiences anxiety occasionally, but persistent anxiety can reduce your quality of life. Though likely best known for altering behavior, worry can have negative effects on our electrodes health. Anxiety speeds up our heartbeat and breathing, concentrating blood flow to the parts of our brains that need it. You are getting ready for a electrodes situation by having this extremely bodily reaction. Test performance may be impacted by anxiety. According to studies, pupils with low levels of test anxiety perform better on multiple-choice question (MCQ) exams than pupils with high levels of anxiety. Studies have indicated that female students have greater levels of test anxiety than male students.

Learn more about anxiety here:

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A gold bar is contain 3.0 mol of gold, how many atoms of gold are in the bar

kenny6666 [7]

Answer:

18.066 x 10^23 atoms of Au

Explanation:

ONE mole = 6.022 x 10^23 particles

3 x 6.022 x 10^23

6 0

2 years ago

Check all that apply.

White raven [17]

Answer:

4 for C in CH4

+4 for C in CO2

-2 for O in all substances

+1 for H in both CH4 and H2O

option 1,2,3 and 4 are correct. Option 5 is not correct

Explanation:

Step 1: Data given

Oxidation number of H = +1

Oxidation number of O = -2

Step 2: The balanced equation

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: The oxidation numbers

-4 for C in CH4

⇒ Oxidation number of H = +1

⇒ 4x +1 = +4

C has an oxidation number of -4

This is correct.

+4 for C in CO2

⇒ Oxidation number of O = -2

⇒ 2x -2 = -4

C has an oxidation number of +4

This is correct.

-2 for O in all substances

⇒ this is correct, the oxidation number of O is always -2 (except in H2O2 and Na2O2)

This is correct.

+1 for H in both CH4 and H2O

⇒ this is correct, the oxidation number of H is always +1 (except in metal hydrides).

This is correct.

+4 for O in H2O

⇒ Oxidation number of H = +1

⇒ 2x +1 = +2

The oxidation number of O is -2

This is not correct

5 0

3 years ago

What makes a colloidal dispersion stable?

alexgriva [62]

1.regulating ph
2.heating
3.adding some oppositely charged colloids

6 0

3 years ago

Read 2 more answers

1.72 moles of NOCI were placed in a 2.50 L reaction chamber

elena-14-01-66 [18.8K]

The equilibrium constant, Kc=0.026

<h3>Further explanation</h3>

Given

1.72 moles of NOCI

1.16 moles of NOCI remained

2.50 L reaction chamber

Reaction

2NOCI(g) = 2NO(g) + Cl2(g).

Required

the equilibrium constant, Kc

Solution

ICE method

2NOCI(g) = 2NO(g) + Cl2(g).

I 1.72

C 0.56 0.56 0.28

E 1.16 0.56 0.28

Molarity at equilibrium :

NOCl :

$\tt \dfrac{1.16}{2.5}=0.464$

NO :

$\tt \dfrac{0.56}{2.5}=0.224$

Cl2 :

$\tt \dfrac{0.28}{2.5}=0.112$

$\tt Kc=\dfrac{[NO]^2[Cl_2]}{[NOCl]^2}\\\\Kc=\dfrac{0.224^2\times 0.112}{0.464^2}=0.026$

4 0

3 years ago

Aqueous hydrochloric acid reacts with solid manganese(iv) oxide to form aqueous manganese(ii) chloride, liquid water and chlorin

maria [59]

4HCl + MnO₂ → MnCl₂ + 2H₂O + Cl₂

2Cl⁻ → Cl₂ + 2e⁻
MnO₂ + 4H⁺ + 2e⁻ → Mn²⁺ + 2H₂O

2Cl⁻ + MnO₂ + 4H⁺ → Cl₂ + Mn²⁺ + 2H₂O

7 0

4 years ago

Read 2 more answers