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Inessa05 [86]
3 years ago
8

I don't understand this part? Plz help =)

Chemistry
1 answer:
Murljashka [212]3 years ago
5 0
Search up the question on here and it will pop up I hope that helps
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30 POINTS! ----- How many moles of oxygen gas are needed to completely react with 145 grams of aluminum? Report your answer with
gladu [14]
First a balanced reaction equation must be established:
4Al _{(s)}    +   3 O_{2}  _{(g)}     →    2 Al_{2} O_{3}

Now if mass of aluminum = 145 g
the moles of aluminum = (MASS) ÷ (MOLAR MASS) = 145 g ÷ 30 g/mol
                                                                                    =  4.83 mols

Now the mole ratio of Al : O₂ based on the equation is  4 : 3  
                                                                [4Al  + 3 O₂ → 2 Al₂O₃]

∴ if moles of Al = 4.83 moles
  then moles of O₂ = (4.83 mol ÷ 4) × 3
                              =  3.63 mol   (to  2 sig. fig.) 

Thus it can be concluded that 3.63 moles of oxygen is needed to react completely with 145 g of aluminum. 


     
4 0
3 years ago
Fill in the coefficients that will balance the following reaction: a0Ca + a1CO2 + a2O2 → a3CaCO3
VashaNatasha [74]
The chemical equation without coefficients is:


Ca + CO2 + O2 --------> Ca CO3


You can balance that equation by trial an error.


This is the chemical equation balanced:


2Ca + 2CO2 + O2 --------> 2Ca CO3


Count the atoms on each side to check the balance


Atom    Left side         right side

Ca         2                     2 

C           2                     2

O          2*2 + 2 = 6       2*3 = 6


Then those are the coefficients:

a0 = 2

a1 = 2

a2 = 1

a3 = 2
6 0
3 years ago
Is dynamite an atom or a molecule?
kkurt [141]

Answer:

TNT is a molecule

Explanation:

4 0
3 years ago
Read 2 more answers
What is the partial pressure of a gas mixture in a mixture of gases?
lesantik [10]
The answer is b. The sum of the individual gas pressure in the mixture
8 0
3 years ago
Read 2 more answers
Calculate the concentration in % (m/m) of a solution containing 30.0g of mgcl2 dissolved in 270.0g of h20
qaws [65]
As the question tells you, you need to use the formula

% mass= mass of solute/ mass of solution x 100

mass solute= 30.0 g
mass of solution= 30.0 + 270.0= 300.0 g

% mass= 30.0/ 300.0 x 100= 10%

answer is B
4 0
3 years ago
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