Step one calculate the moles of each element
that is moles= % composition/molar mass
molar mass of Ca = 40g/mol, S= 32 g/mol , O= 16 g/mol
moles of Ca = 29.4 /40g/mol=0.735 moles, S= 23.5/32 =0.734 moles, O= 47.1/16= 2.94 moles
calculate the mole ratio by dividing each mole with smallest mole that is 0.734
Ca= 0.735/0.734= 1, S= 0.734/0.734 =1, O = 2.94/ 0.734= 4
therefore the emipical formula = CaSO4
Heat is like the fire it’s hot.
I think it’s B
Sorry if I’m wrong
Answer:
Molar concentration of CO₂ in equilibrium is 0.17996M
Explanation:
Based on the reaction:
NiO(s) + CO(g) ⇆ Ni(s) + CO₂(g)
kc is defined as:
kc = [CO₂] / [CO] = 4.0x10³ <em>(1)</em>
As initial concentration of CO is 0.18M, the concentrations in equilibrium are:
[CO] = 0.18000M - x
[CO₂] = x
Replacing in (1):
4.0x10³ = x / (0.18000-x)
720 - 4000x = x
720 = 4001x
x = 0.17996
Thus, concentrations in equilibrium are:
[CO] = 0.18000M - 0.17996 = 4.0x10⁻⁵
[CO₂] = x = <em>0.17996M</em>
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Thus, <em>molar concentration of CO₂ in equilibrium is 0.17996M</em>
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I hope it helps!
Answer:
pOH = 9.
Explanation:
The inverse relationship between the pH and pOH of any given solution can be written as:
pH = 14 - pOH
Or conversely:
pOH = 14 - pH
With the above information in mind we can <u>use the given pH to calculate the pOH</u>:
pOH = 14 - pH
pOH = 14 - 5
pOH = 9
Thus, black coffee has a pOH of 9.
<h3>
Answer:</h3>
1.9 moles
<h3>
Explanation:</h3>
Carbon dioxide (CO₂) is a compound that is made up of carbon and oxygen elements.
It contains 2 moles of oxygen atoms and 1 mole of carbon atoms
Therefore;
We would say, 1 mole of CO₂ → 2 moles of Oxygen atoms + 1 mole of carbon atoms
Thus;
If a sample of CO₂ contains 3.8 moles of oxygen atoms we could use mole ratio to determine the moles of CO₂
Mole ratio of CO₂ to Oxygen is 1 : 2
Therefore;
Moles of CO₂ = 3.8 moles ÷ 2
= 1.9 moles
Hence, the moles of CO₂ present in a sample that would produce 3.8 moles of Oxygen atoms is 1.9 moles
