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Inessa05 [86]
3 years ago
8

I don't understand this part? Plz help =)

Chemistry
1 answer:
Murljashka [212]3 years ago
5 0
Search up the question on here and it will pop up I hope that helps
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The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
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Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

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0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

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72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

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