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2 years ago

I don't understand this part? Plz help =)

Chemistry

1 answer:

Murljashka [212]2 years ago

5 0

Search up the question on here and it will pop up I hope that helps

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The ____ is the time required for one half of the atoms of a radio scope to ____.

mash [69]

First blank is: Half-Life
Second Blank is: decay into its products

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3 years ago

Rocks and sand are nonliving .all organisms are

solong [7]

Hey there!

Rocks and sand are nonliving. All organisms are living.
Living organisms have five characteristics. Living organisms respond to a stimulus, need energy, grow, reproduce, and get rid of wastes. All living organisms consist of cells.

Hope this helps! Have a Brainly day! :D

5 0

3 years ago

how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate

Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

$3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3$

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

$0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})$

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

$63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})$

= $95.7gNaClO_3$

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.

$95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})$

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0

3 years ago

Give an example of a solution that can be seperated by simple distilation.

Juliette [100K]

Answer: Evaporation of salt water

Explanation: During the process of evaporating salt water which involves simple distillation, pure water is separated with salt molecules.

When heated water evaporates from the solution since it is less dense. When condensed it becomes pure water and salt is left out since it is more denser.

8 0

2 years ago

Consider two solutions: solution x has a ph of 4; solution y has a ph of 7. from this information, we can reasonably conclude th

KIM [24]

<span>Consider two solutions: solution X has a pH of 4; solution Y has a pH of 7. From this information, we can reasonably conclude that </span>the concentration of hydrogen ions (H⁺) or hydronium ions (H₃O⁺) in solution X is thousand times as great as the concentration of hydrogen ions or hydronium ions in solution Y.
Solution X: c(H⁺) = 10∧-pH = 10⁻⁴ mol/L = 0,0001 mol/L.
Solution Y: c(H⁺) = 10⁻⁷ mol/L = 0,0000001 mol/L.
0,0001 mol/L / 0,0000001 mol/L = 1000.

3 0

2 years ago