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3 years ago

What component of air causes the flame in a bunsen burner to become bluer?

Chemistry

1 answer:

Lyrx [107]3 years ago

7 0

<h3><u>Answer;</u></h3>

Oxygen

<h3><u>Explanation;</u></h3>

<em><u>A bunsen burner attains a blue gas flame when there is enough oxygen for complete combustion. </u></em>
When there is sufficient oxygen, the gas flame appears blue because complete combustion creates enough energy to excite and ionize the gas molecules in the flame.
In other words; increasing oxygen supply, less black body-radiating soot is produced as a result of a more complete combustion and the reaction creates enough energy to excite and ionize gas molecules in the flame, and a blue flame is formed.

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A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti

MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

$H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_3H_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL$

Putting values in above equation, we get:

$2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M$

Thus the molarity of the malonic acid solution is 0.08335 M

5 0

3 years ago

What is the best description of the side of the moon that faces earth?

Delicious77 [7]

D. Changes

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4 0

3 years ago

Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) At 25°C, for this reaction,

insens350 [35]

Answer:

401.17 K is the minimum temperature at which the reaction will become spontaneous under standard state conditions.

Explanation:

The expression for the standard change in free energy is:

$\Delta G=\Delta H-T\times \Delta S$

Where,

$\Delta G$ is the change in the Gibbs free energy.

T is the absolute temperature. (T in kelvins)

$\Delta H$ is the enthalpy change of the reaction.

$\Delta S$ is the change in entropy.

Given at:-

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25.0 + 273.15) K = 298.15 K

$\Delta H$ = 128.9 kJ/mol

$\Delta G$ = 33.1 kJ/mol

Applying in the above equation, we get as:-

$33.1=128.9-298.15\times \Delta S$

$-29815\Delta S=-9580$

$\Delta S=-9580$ = 0.32131 kJ/Kmol

So, For reaction to be spontaneous, $\Delta G$

Thus, For minimum temperature:-

$\Delta H-T\times \Delta S=0$

$128.9-T\times 0.32131=0$

$T=\frac{128.9}{0.32131}=401.17\ K$

<u>Hence, 401.17 K is the minimum temperature at which the reaction will become spontaneous under standard state conditions.</u>

6 0

3 years ago

Write a balanced chemical equation for the reaction of copper(II) sulfate and concentrated ammonia to produce teramine copper(II

Rudiy27

Answer:

CuSO4(aq) + 4NH3(aq) + nH2O→ [Cu(NH3)4H2On]S04(aq)

Explanation:

When the concentrated ammonia is added into the copper ions solution, a blue solid is formed. This blue solid is gelatinous.it consist of Cu(OH)2 in insoluble form. As more ammonia is added precipitate start to dissolve and [Cu(NH3)4]∧+2 is produce.

Net Ionic equation:

Cu∧+2 +4NH3 → [Cu(NH3)4]∧+2

S04∧-2 are spectator ions.

Properties and uses of Tetraaminecopper(ll) sulfate:

1. It is solid compound.

2. Its color is dark blue.

3. It has ammonia like odor.

4. It is used to make the copper compounds and also used in the printing of fabric.

5. It is also used as pesticide.

3 0

3 years ago

I need the answer today!

olchik [2.2K]

_____________________________________________

<h2 /><h2 /><h2><u>Solution </u><u>3</u><u> Is The Most Concentrated</u></h2>

M = m/v

= 100ml ÷ 2 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

M = m/v

= 200ml ÷ 5 spoons × 100%

= - 4,000 μg/ppb³

= <u>40% Diluted</u>

M = m/v

= 300ml ÷ 6 spoons × 100%

= - 5,000 μg/ppb³

= <u>50% Diluted</u>

M = m/v

= 600ml ÷ 8 spoons × 100%

= - 75,000 μg/ppb³

= <u>75% Diluted</u>

_____________________________________________

8 0

3 years ago