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nalin [4]
3 years ago
13

What component of air causes the flame in a bunsen burner to become bluer?

Chemistry
1 answer:
Lyrx [107]3 years ago
7 0
<h3><u>Answer;</u></h3>

Oxygen

<h3><u>Explanation;</u></h3>
  • <em><u>A bunsen burner attains a blue gas flame when there is enough oxygen for complete combustion. </u></em>
  • When there is sufficient oxygen, the gas flame appears blue because complete combustion creates enough energy to excite and ionize the gas molecules in the flame.
  • In other words; increasing oxygen supply, less black body-radiating soot is produced as a result of a more complete combustion and the reaction creates enough energy to excite and ionize gas molecules in the flame, and a blue flame is formed.
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Explanation:

HF has the largest dipole moment, you can tell which molecule has the largest by looking on the periodic table, they are usually the pair that are furthest from each other and it is also due to them having the biggest difference in electronegativity, usually the closer two elements are, the weaker the dipole moment.

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Which planet listed below will take the longest amount of time to orbit the sun?
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3 years ago
Assume that concentrated aqueous NH3 has a density of 0.252 g/mL (0.252 g of NH3 per mL of liquid). Calculate the volume of NH3
Kobotan [32]

The question is incomplete, here is the complete question:

Assume that concentrated aqueous NH₃ has a density of 0.252 g/mL (0.252 g of NH₃ per mL of liquid). Calculate the volume of NH₃ required to contain 0.442 mol?

<u>Answer:</u> The volume of ammonia required is 29.82 mL

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 0.442 moles

Putting values in above equation, we get:

0.442mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=(0.442mol\times 17g/mol)=7.514g

To calculate the volume of ammonia, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of ammonia = 0.252 g/mL

Mass of ammonia = 7.514 g

Putting values in above equation, we get:

0.252g/mL=\frac{7.514g}{\text{Volume of ammonia}}\\\\\text{Volume of ammonia}=\frac{7.514g}{0.252g/mL}=29.82mL

Hence, the volume of ammonia required is 29.82 mL

4 0
3 years ago
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