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agasfer [191]
3 years ago
10

A random number generator generates numbers from 1 to 10. What is the probability that the number generator generates a 3 ?

Mathematics
2 answers:
AveGali [126]3 years ago
7 0

Answer:

1/10

Step-by-step explanation:

qaws [65]3 years ago
7 0
The probability is that it will be 1/10
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Answer:

20 Km per hour.

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3 years ago
Use the point-slope form linear equation given.
Agata [3.3K]

y-3=3(x+1)

opening the bracket

y-3=3x+3

y=3x+3+3

equation of the line in the form y=mx+c;

y=3x+6

therefore gradient=3

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y--3/x-0=3

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y+3=3x-0

y=3x-3.

8 0
3 years ago
Select the missing numbers. Remember to indicate a negative cash flow with parentheses.
cluponka [151]

To find the cash flow, subtract the Cash Disbursements from the sales receipts for each month.


January: 110 - 135 =  -$25

February: 85 - 110 = -$25

March: 100 - 95 = $5

April: 130 - 95 = $35

May: 145 - 100 = $45

June: 165 - 105 = $60

4 0
3 years ago
Which of the following is closest to the area of the shaded region below?
enot [183]

Answer:

C is the answer

Step-by-step explanation:

Find the area of the whole circle, r=12cm

=pie× radius sq

=3.14×12×12

=<u>452.16cm sq</u>

The are of the smaller circle, r=6cm

=same formula

=3.14×6×6

=<u>113.04cm sq</u>

<u>Subtract</u><u> </u><u>them</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>shaded</u><u> </u><u>region</u><u> </u>

452.16 - 113.04

=339.12

<em>Closest</em><em> </em><em>is</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>339</em><em> </em><em>cm</em><em> </em><em>sq</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>c</em>

<em>Hope</em><em> </em><em>it's</em><em> </em><em>helpful</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em> </em>

5 0
3 years ago
The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci
Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that n = 300 and \pi = \frac{10}{300} = 0.033

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532

The correct answer is

(0.0128, 0.0532)

4 0
3 years ago
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