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Mekhanik [1.2K]
3 years ago
7

Find the measure of A Options -14 63 96 44 I need help ASAP

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

Step-by-step explanation:because all angles in a triangle add up to 180° 100°+30°=130° 180°-130°=50°

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What is the maximum y value
satela [25.4K]

Answer: 15?

Step-by-step explanation:

On the y axis it between so it should be 15

6 0
3 years ago
Read 2 more answers
To pass a course with an Upper A ​grade, a student must have an average of 90 or greater. A​ student's grades on three tests are
kipiarov [429]

Answer:

The student must get at least 86 in the next text in order to get an upper A average.

Step-by-step explanation:

The scores in the three tests are: 91, 94 and 89

The average score here is \frac{91 + 94 + 89}{3} = 91 (rounded off to nearest whole number)

In order to get an Upper A average after tackling the next test, the students total score in the four tests must be 90 × 4 = 360

Let's say the student scores x in the fourth test.

Then; 91 + 94 + 89 + x ≥ 360

274 + x  ≥ 360

x ≥ 360 - 274

x ≥ 86

3 0
3 years ago
Find Lowest common factor of following questions .<br>56, 42, 28​
Montano1993 [528]

Answer:

\boxed{\textsf{ The LCM of 56 , 42 , 28 is \textbf{ 168}.}}

Step-by-step explanation:

We need to find out the LCM of 56 , 42 , 28 . So Lowest Common Multiple known as LCM is the lowest multiple which is divisible by all the numbers whose LCM is taken out . It can we done by two methods. Both of which are discussed in the attachment .

For complete solution kindly refer to the attachment .

<u>Related</u><u> Information</u><u> </u><u>:</u><u>-</u><u> </u>

<u>•</u><u> </u><u>HCF </u><u>:</u><u>-</u>

  • It stands for Highest Common Factor . It is the highest numbers which divides out completely the numbers without leaving remainder of the numbers whose HCF is we are finding out .

3 0
3 years ago
Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1
garik1379 [7]

Answer:

d=1.28\times 10^{-6}\ g/cm^3

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3

So, the density of the bag is 1.28\times 10^{-6}\ g/cm^3.

7 0
2 years ago
Please help asap I will give you brainliest Find the area of the shaded region
kondaur [170]

Answer:

36

Step-by-step explanation:

Area of total region = 12 ×5

=60

Area of the small region = 8×3

=24

Area of shaded region = Area of Total region - area of small region

= 60 - 24

= 36

4 0
2 years ago
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