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3 years ago

Find the sum of 12/13 +(-1/3)

Mathematics

1 answer:

Arlecino [84]3 years ago

5 0

Answer:

23/39

Step-by-step explanation:

Step 1:

12/13 + ( - 1/3 )

Step 2:

36/39 - 13/39

Answer:

23/39

Hope This Helps :)

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How many solutions does 2(x-3)=10x-6-8x

Step2247 [10]

Answer: Infinitely many

Step-by-step explanation: 2(x-3)=10x-6-8x

2x-6=10x-6-8x

2x-6=2x-6

4 0

3 years ago

Is 0.007x10 equivalent to 0.07

djverab [1.8K]

Answer: yes.

Step-by-step explanation:

adding 10 is moving the decimal point once to the right, so yes.

move the decimal point in 0.007 once to the right (multiply it by 10) and you get 0.07

5 0

2 years ago

Read 2 more answers

How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$