Answer:
2 cubic meters
Explanation:
Suppose ideal gas, when the temperature stays constant, then the product of pressure and volume is the same as before
where are the pressure and volume of the gas before. are the pressure and volume of the gas after. We can solve for the volume after
Answer:It started at 20°C, the bras and the iron must b cooled at -150°C.
Explanation:
The formular for linear expansion is given by:
L = Lo + Lo&◇T
Where L = linear dimensions)diameter) after temperature change.
Lo=Original linear dimension
&= Coefficient of thermal expansion for the material.
◇T=Change in temperature.
At some temperature,L(brass)=L(iron)
Lo + Lo&◇T = Lo + Lo&◇T
8.753cm + 8.753cm×(8.7×10^-6C^-1)×◇T=8.753cm+ 8.753cm ×(12.0×10^-6C^-1)×◇T
8.753+(1.636×10^-4)◇T= 8.753+(1.049×10^-4C^-1)◇T
5.87 × 10^-5◇T= 0.010
◇T= 0.010/(5.87×10^-5)
◇T= 170°C
◇T=T1-T2
T= (20 - 170)°C
T= -150°C
Answer:
a.She is moving in a constant speed
b.she is travelling ever 10 minutes every 1 distance
Explanation:
Answer:
<em>x=6.39 m</em>
Explanation:
<u>Rectangular Components of a Vector</u>
Vectors can be expressed in several forms, including the magnitude-angle form, and the rectangular-coordinates form.
If the magnitude r and angle β are given, we can find the rectangular coordinates (x,y) as follows:
The vector of the question has a magnitude of r=9.55 m and an angle β=-48°. The x-component is:
Using a digital calculator:
x=6.39 m
Answer:
By Factor of 4
Explanation:
The expression for centripetal acceleration is given as,
a = v²/r........... equation 1
Where a = centripetal acceleration, v = speed, r = radius of the circle.
Case 1
Given: v = 150 m/s, r = 500 m
Substitute into equation 1
a = 150²/500
a = 22500/500
a = 45 m/s².
Case 2
Given: v = 300 m/s, r = 500 m
Also substitute into equation 1
a = 300²/500
a = 180 m/s²
Factor of change of the acceleration = 180/45
Factor of change of the acceleration = 4.
Hence the acceleration will change by a factor of 4