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dlinn [17]
3 years ago
14

When velocity is graphed with respect to time, what does the area under

Physics
2 answers:
denpristay [2]3 years ago
6 0
The Answer

Is Displacement
Juliette [100K]3 years ago
4 0

Answer:

the answer is D

Explanation:

Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.

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An overtone that's a whole number multiple of the fundamental frequency of a string is called a
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The correct answer in this case is B. Harmonic.

The remaining answers refer to other parts of a musical composition, and some such as the pitch can even be found in the study of human voice. 
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People who drink coffee are more likely to develop cancer
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Answer:

The answer is False

8 0
2 years ago
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You are standing on a skateboard, initially at rest. a friend throws a very heavy ball towards you. you can either catch the obj
PIT_PIT [208]

<span>You should deflect the ball in order to maximize your speed on the skateboard.

Since this creates a larger impulse, you want to deflect the ball. Splitting it up into catching and throwing the ball may by something you can think of deflecting the ball. First, you need to catch the ball, which in turn would push you forward with some speed. (The speed we are talking about should obviously be equal to option A, where you catch the ball). Now, throw the ball back to him since these two processes are equal to deflecting the ball. Throwing a mass away from you would cause or enable you to move even fast.</span>

7 0
2 years ago
Hanging from a horizontal beam are nine simple pendulums of the following lengths:
LenaWriter [7]

Answer:

Options d and e

Explanation:

The pendulum which will be set in motion are those which their natural frequency is equal to the frequency of oscillation of the beam.

We can get the length of the pendulums likely to oscillate with the formula;

L =\frac{g}{w^{2} }

where g=9.8m/s

         ω= 2rad/s to 4rad/sec

when ω= 2rad/sec

L= \frac{9.8}{2^{2} }

L = 2.45m

when  ω= 4rad/sec

L=\frac{9.8}{4^{2} }

L = 9.8/16

L=0.6125m

L is between 0.6125m and 2.45m.

This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead

8 0
3 years ago
Which of these BEST describes the term ecliptic? A. the circle where "Earth meets the sky" B. the change in azimuth and altitude
jeyben [28]
I'll say B ....hope that helps...
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3 years ago
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