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3 years ago

When velocity is graphed with respect to time, what does the area under

Physics

2 answers:

denpristay [2]3 years ago

6 0

The Answer

Is Displacement

Juliette [100K]3 years ago

4 0

Answer:

the answer is D

Explanation:

Since the velocity of the object is the derivative of the position graph, the area under the line in the velocity vs. time graph is the displacement of the object.

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Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charg

bekas [8.4K]

Answer:

$5.3\times 10^3 N/C$

Explanation:

We are given that

Distance between plates=d=2.2 cm= $2.2\times 10^{-2} m$

$1 cm=10^{-2} m$

$\sigma=47nC/m^2=47\times 10^{-9}C/m^2$

Using $1 nC=10^{-9} C$

We have to find the magnitude of E in the region between the plates.

We know that the electric field for parallel plates

$E=\frac{\sigma}{2\epsilon_0}$

$E_1=\frac{\sigma}{2\epsilon_0}$

$E_2=\frac{\sigma}{2\epsilon_0}$

$E=E_1+E_2$

$E=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}$

Where $\epsilon_0=8.85\times 10^{-12}C^2/Nm^2$

Substitute the values

$E=\frac{47\times 10^{-9}}{8.85\times 10^{-12}}$

$E=5.3\times 10^3 N/C$

Hence, the magnitude of E in the region between the plates= $5.3\times 10^3 N/C$

5 0

3 years ago

Answering the following questions will help you to focus on the outcomes of these experiments:

kotykmax [81]

Answer:

Explanation:

Because friction is always present, the actual mechanical advantage of a machine is always less than the ideal mechanical advantage.

7 0

3 years ago

Read 2 more answers

A 1,000 kg car is moving at 20 m/s, and slams into a building before coming to a halt.

ale4655 [162]

Hi there!

We can calculate linear momentum using the following:
$\large\boxed{p = m v}$

p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)

Calculate:

$p = 1000 * 20 = 20000 kg\frac{m}{s}$

Now, we can relate force, time, and momentum with the following:
$\large\boxed{I = Ft}\\\\$

I = Impulse (kgm/s)
F = Force (N)
t = time (s)

Rearrange to solve for force:
$F = \frac{I}{t}$

The impulse is equal to the change in momentum. Since the car comes to a halt, all of its momentum is lost, so:

$I = \Delta p = p_f - p_i = 0 - 20000 = -20000$

Solve:
$F = \frac{-20000}{0.5} = \boxed{-40000N}$

**Negative force since the positive direction is towards the wall, and the negative direction is away from the wall.

7 0

3 years ago

What formula can be used to determine the velocity of an object in free fall?

PtichkaEL [24]

Assuming that you're given either an initial or final velocity, you can use the following equation and solve for the initial or final velocity.

Vyf² = Vyi² - 2g(y - y₀)

Where,
Vyf² = final velocity
Vyi₂² = initial velocity
g = 9.81 m/s²
(y - y₀) = the change in the distance along the y-axis.

You'll need also determine the positive and negative of your y-axis for your final solution because velocity can be positive or negative based on direction. Lastly, don't forget to square root both sides of your equation for your velocity.

I hope this helps.

4 0

3 years ago

A rocket travels at a speed of 14,000 m/s. What is the distance travelled by the rocket in 150s?

kati45 [8]

1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

$v=\frac{S}{t}$