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Setler [38]
3 years ago
6

What are the products? 1. 854 and 68 2. 403 and 42

Mathematics
1 answer:
aksik [14]3 years ago
6 0
1. 58,072
2. 16,926

Hope this helps you!
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Simplify 3x+5y-x+2y please
V125BC [204]

Answer:

2x+7y

Step-by-step explanation:

<u>3x</u>+5y<u>-x</u>+2y =

<u>3x-x</u> = 2x

5y+2y = 7y

3x+5y-x+2y = 2x+7y

5 0
3 years ago
Find all polar coordinates of point p where p = ordered pair 5 comma pi divided by 3.
Aleonysh [2.5K]

Find all polar coordinates of point p where p = ordered pair 5 comma pi divided by 3.

The polar coordinate of any point can be written as:

<span>(r, θ) = (r, θ + 2nπ)                                           --> when positive</span>

<span> (r, θ) = [ - r, θ + (2n + 1)π ]                           --> when negative</span>

<span> where n is any integer.</span>

The polar coordinates of this given point P is: P = (r, θ) = (5, π/3).

When the value of r is positive, the polar coordinate is written as P= (5, π/3) = (5, π/3 + 2nπ)

where n is any integer.

When the value of r is negative, the polar coordinate is written as P = (5, π/3) = [ - 5, π/3 + (2n + 1)π] where n is any integer.

 

Therefore all polar coordinates of point P are (5, π/3 + 2nπ) and [ - 5, π/3 + (2n + 1)π ].

<span> </span>

7 0
3 years ago
Find the height of a cone with a volume of 150 in^3 and a diameter of 20 in. Use 3.14 for π.
Zolol [24]

Volume = \frac{1}{3} \pi r^{2} h

150 = \frac{1}{3} x 3.14 x 10 x 10 x h

150 x 3 = 314 x h

h = 450/314

h = 1.43 inches

6 0
3 years ago
The image shows a geometric representation of the function f(x)=x^2-2x-6 written in standard form. What is the function written
Degger [83]
Y=(x-1)^2-7 This is this function in vertex form
9 0
3 years ago
Read 2 more answers
I need help with this somebody help
Mariulka [41]

Answer:

Width: x + 3

(Length, width):

(5,4) (6,5) (7,6)

Step-by-step explanation:

x² + 7x + 12

x² + 4x + 3x + 12

x(x + 4) + 3(x + 4)

(x + 4)(x + 3)

Longer one is the length,

With is (x + 3)

x = 1,

5 × 4

x = 2,

6 × 5

x = 3,

7 × 6

3 0
3 years ago
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