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olchik [2.2K]
2 years ago
11

An object with a mass of 3kg has a momentum of 75 kg m/s what is its velosity

Physics
2 answers:
MaRussiya [10]2 years ago
7 0

                      Momentum = (mass) x (velocity)

Since we have no information about the object's direction,
the best we can do is use the magnitude of its momentum
and find it's speed.

               Magnitude of Momentum = (mass) x (speed)

For this object,             (75 kg-m/s) = (3 kg) x (speed)

Divide each side by (3kg):

                         (75 kg-m/s) / (3 kg)  =  Speed

                                             Speed  =  25 m/s .

                                                  (about  56 mph)

kirill115 [55]2 years ago
6 0
p=75 \ kg \cdot m/s \\ m=3 \ kg \\ \boxed{v-?} \\ \bold{Solving:} \\ \boxed{p=m \cdot v} \\ \Rightarrow v= \frac{p}{m} \\ v= \frac{75 \ kg \cdot m/s}{3 \ kg} \\ \Rightarrow \boxed{v=25 \ m/s}
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3 years ago
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No. 
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3 0
2 years ago
a lorry travels 3600m on a test track accelerating constantly at 3m/s squared from standstill. what is the final velocity (3 sig
suter [353]

The final velocity of the truck is found as 146.969 m/s.

Explanation:

As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.

Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.

2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}

Then, the final velocity will be

v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s

Thus,  the final velocity of the truck is found as 146.969 m/s.

8 0
3 years ago
A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol
PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula E = \dfrac{kq }{d}

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

7 0
3 years ago
Mass, volume and density are all properties of
snow_tiger [21]

Answer:

Properties of matter

Explanation:

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7 0
3 years ago
Read 2 more answers
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