Help me please…………….

Suppose you want to make an interferometer with two slits to show the wave nature of light to your friends. The most convenient

nevsk [136]

Answer:

a) the pattern is bright, b) y = 8.25 mm, c) the distance increases with the wavelength increases

Explanation:

This is a team building exercise to perform interference experiments, where the separation of the slits is d = 1 m = 1 10⁻³ m and the distance to the screen L = 1.5 m

Constructive interference occurs when the path difference is equal to an integer number of wavelengths

d sin θ = m λ

a) The center of the two-ray pattern has the same length so the intensity is MAXIMUM, that is, the pattern is bright

b) to find the distance let's use trigonometry

tan θ= y / L

tan θ =sin θ/cos θ= sin θ

because the angles are small

we substitute

y = $\frac{m \lambda L}{d}$

let's calculate

y = 10 550 10⁻⁹ 1.5 / 1 10⁻³

y = 8.25 10⁻³ m

c) for this part the incident light must be white or polychrome light

let's find the distance (y) for some colors, in the first order

Violet λ = 400

y = 1 400 10⁻⁹ 1.5 / 1 10⁻³

y = 6 10⁻⁴ m

green λ = 500 nm

y = 1 500 10⁻⁹ 1.5 / 1 10⁻³

y = 7.5 10⁻⁴ m

yellow λ = 600 nm

y = 1 600 10⁻⁹ 1.5 / 1.10⁻³

y = 9 10⁻⁴ m

lam λ = 700 nm

y = 1 700 10⁻⁹ 1.5 / 1. 10⁻³

y = 1.05 10⁻³ m

violet, green, orange, red

the distance increases with the wavelength increases

d) To find the wavelength we must measure the distance y from the center of the slit for various interference orders and using the equation we can find the wavelength of rationality

4 0

3 years ago

An engineer in India (standard household voltage = 220 volts) is designing a transformer for use on her

Gnom [1K]

He should a step-up transformer with k=220/120=1.83 so output coil must have 240*1.83=440 turns

5 0

3 years ago

16)

VMariaS [17]

Answer:

a.proton, proton

hope this helped :) have a goodday

6 0

3 years ago

A block of mass 12.2 kg is sliding at an initial velocity of 3.9 m/s in the positive x-direction. The surface has a coefficient

Studentka2010 [4]

Answer:

Explanation:

a) Force of friction = μ R where μ is coefficient of kinetic friction and R is reaction force

R = mg where m is mass of the block

Force of friction F = μ x mg

= .173 x 12.2 x 9.8

= 20.68 N

b ) Only force of friction is acting on the body so

deceleration = force / mass = 20.68 / 12.2 = 1.7 m /s²

acceleration = - 1.7 m /s²

c )

v² = u² - 2 a s

v = 0 , u = 3.9 m /s

a = 1.7 m /s

0 = 3.9² - 2 x 1.7 x s

s = 4.47 m

5 0

2 years ago

A brick of mass 5 kg is released from rest at a height of 3 m. How fast is it going when it hits the ground? Acceleration due to

sineoko [7]

Taking into account the definition of kinetic, potencial and mechanical energy, when the brick hits the ground, it has a speed of 7,668 m/s.

<h3>Kinetic energy</h3>

Kinetic energy is a form of energy. It is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.

Kinetic energy is defined as the amount of work necessary to accelerate a body of a given mass and at rest, until it reaches a given speed. Once this point is reached, the amount of accumulated kinetic energy will remain the same unless there is a change in speed or the body returns to its state of rest by applying a force.

The kinetic energy is represented by the following expression:

Ec= ½ mv²

Where:

Ec is the kinetic energy, which is measured in Joules (J).
m is the mass measured in kilograms (kg).
v is the speed measured in meters over seconds (m/s).

<h3>Potential energy</h3>

On the other hand, potential energy is the energy that measures the ability of a system to perform work based on its position. In other words, this is the energy that a body has at a certain height above the ground.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the force of gravity.

So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

Where:

Ep is the potential energy in joules (J).
m is the mass in kilograms (kg).
h is the height in meters (m).
g is the acceleration of fall in m/s².

<h3>Mechanical energy</h3>

Finally, mechanical energy is that which a body or a system obtains as a result of the speed of its movement or its specific position, and which is capable of producing mechanical work. Then:

Potential energy + kinetic energy = total mechanical energy

<h3>Principle of conservation of mechanical energy </h3>

The principle of conservation of mechanical energy indicates that the mechanical energy of a body remains constant when all the forces acting on it are conservative (a force is conservative when the work it does on a body depends only on the initial and final points and not the path taken to get from one to the other.)

Therefore, if the potential energy decreases, the kinetic energy will increase. In the same way, if the kinetics decreases, the potential energy will increase.

A brick of mass 5 kg is released from rest at a height of 3 m. Then, at this height, the brick of mass has no speed, so the kinetic energy has a value of zero because it depends on the speed or moving bodies. But the potential energy is calculated as:

Ep= 5 kg× 9.8 $\frac{m}{s^{2} }$ × 3 m

Solving:

So, the mechanical energy is calculated as:

Potential energy + kinetic energy = total mechanical energy

147 J + 0 J= total mechanical energy

147 J= total mechanical energy

The principle of conservation of mechanical energy can be applied in this case. Then, when the brick hits the ground, the mechanical energy is 147 J. In this case, considering that the height is 0 m, the potential energy is zero because this energy depends on the relative height of the object. But the object has speed, so it will have kinetic energy. Then:

Potential energy + kinetic energy = total mechanical energy

0 J + kinetic energy= 147 J

kinetic energy= 147 J

Considering the definition of kinetic energy:

½ 5 kg×v²= 147 J

$v=\sqrt{\frac{2x147 J}{5 kg} }$