Answer:
0.976 c
Explanation:
= velocity of object 1 relative to earth = 0.80 c
= velocity of object 2 relative to object 1 = 0.80 c
= velocity of object 2 relative to earth
Velocity of object 2 relative to earth is given as
= 0.976 c
Answer:
66.26 m/s
Explanation:
Horizontal velocity, Vx = 55.3 m/s
Vertical velocity, Vy = 36.5 m/s
The value of the resultant velocity is given by the vector sum of the two velocities which are acting at 90°.
V = 66.26 m/s
Thus, the velocity of the vehicle is 66.26 m/s along its descent path.
Answer:
1) Weight on Mercury
Explanation:
do the same to the rest and use your calculator to find the weight in N.
Answer:
The jet will fly 2400 km.
Explanation:
Given the velocity of the jet flying toward the east is 1,500 kmph toward the east.
We need to find the distance covered in 1.6 hours.
In our problem we are given speed and time, we can easily determine the distance using the following formula.
So, the supersonic jet will travel 2400 km in 1.6 hours toward the east from its starting point.