Question

If a drag racer wins the final round of her race by going an average speed of 198.37 miles per hour in 4.537 seconds, what distance did he cover?

Answer 1

The distance covered by drag racer by going an average speed of 198.37 miles per hour in 4.537 seconds is 0.2500 miles.

Solution:

By using the relationship between distance speed and time, distance is the product of speed and time.

$\begin{array}{l}{\text {Speed}=\frac{\text {Distance}}{\text {Time}}} \\\\ {\text {Distance}=\text {Speed} \times \text {Time}}\end{array}$

Converting seconds to hours,

We know that $1 \text { second }=\frac{1}{3600} \text { hours }$

So, $4.537 \text { seconds }=4.537 \times \frac{1}{3600} \text { hours }$  

Average speed = 198.37 miles per hour and time = $4.537 \times \frac{1}{3600} h o u r s$

$\begin{array}{l}{\text {Distance}=198.37 \frac{\text { miles }}{\text { hours }} \times 4.537 \times \frac{1}{3600} \text { hours }} \\\\ {\text { Distance }=198.37 \times 4.537 \times \frac{1}{3600} \text { miles }=198.37 \times 0.00126} \\\\ {\Rightarrow 0.250001 \approx 0.2500}\end{array}$

Distance = 0.2500 miles

Answer 2

900.00469 miles i think