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natima [27]
3 years ago
15

What are moana's hobbies

Physics
1 answer:
crimeas [40]3 years ago
4 0
The movie? Or the book
You might be interested in
A+10 u charge and a -10 4C (1 HC - 106 C), at a distance of 0.3 m,
Marina CMI [18]

Answer:

B. Attract each other with a force of 10 newtons.

Explanation:

Statement is incorrectly written. <em>The correct form is: A </em>+10\,\mu C<em> charge and a </em>-10\,\mu C<em> at a distance of 0.3 meters. </em>

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}} (1)

Where:

F - Electrostatic force, in newtons.

\kappa - Electrostatic constant, in newton-square meters per square coulomb.

|q_{A}|,|q_{B}| - Magnitudes of electric charges, in coulombs.

r - Distance between charges, in meters.

If we know that \kappa  = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}, |q_{A}| = |q_{B}| = 10\times 10^{-6}\,C and r = 0.3\,m, then the magnitude of the electrostatic force is:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}

F = 9.987\,N

In consequence, correct answer is B.

4 0
3 years ago
A fan blade rotates with angular velocity given by ωz(t)= γ − β t2. part a calculate the angular acceleration as a function of t
Katyanochek1 [597]
Given:

w = z(t)= γ − β*t^2

Differentiating both sides with respect to t, we get:

α = z(t) = -2βt

Given: 
<span> γ = 5.35 rad/s and β = 0.810 rad/s3 
</span>
so, For t = 3 sec,

angular acceleration = -2 * 0.810 * 3 = 
<span>-4.86</span>
8 0
4 years ago
Read 2 more answers
Images produced by a cathode ray tube result from induced emf True or false
3241004551 [841]
I'm not completely sure but i think it's false 
8 0
3 years ago
How is energy sent from Earth to space?
Nostrana [21]
It might be radiation and reflection but I’m not sure
8 0
3 years ago
Read 2 more answers
A lump of clay whose rest mass is 4 kg is travelling at three-fifths the speed of light when it collides head-on with an identic
Harman [31]

Answer:

mass of the composite lump is 10 kg

Explanation:

given data

mass = 4 kg

to find out

mass of composite lump

solution

we know energy is conserved so

so m1 = m2 = m0 that is 4kg

and

E(1) release+ E(2) release = E(1,2) rest

so γ(1)m(1)c² + γ(2)m(2)c²  = Mc²    ..........................1

that why here

|v(1)| = |v(2)| = 3/5 c        ......................2

and

γ = 1 / √(1 − v²/c²)           .......................3

put here v = 3 and c is 5

γ = 1 /√(1 − 9/25)

γ =  5/4

so

γ(1) = γ(2) = γ = 5/4  

so from equation 1

γ(1)m(1)c² + γ(2)m(2)c²  = Mc²

M = 2γm0

M = 2(5/4 )(4)

M = 10 kg

so mass of the composite lump is 10 kg

7 0
4 years ago
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