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irina1246 [14]
3 years ago
7

A boat floats south on the Amazon River at a speed of 6 m/s. The boat and

Physics
1 answer:
EleoNora [17]3 years ago
7 0

Explanation:

Take south to be negative.

a. Momentum is mass times velocity.

p = mv

p = (540 kg) (-6 m/s)

p = -3240 kg m/s

p = 3240 kg m/s south

b. Impulse = change in momentum

J = Δp

Since the mass is constant:

J = mΔv

J = (540 kg) (-4 m/s − (-6 m/s))

J = 1080 kg m/s

J = 1080 kg m/s north

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3 years ago
Liam throws a water balloon horizontally at 8.2 m/s out of a window 18 m from the ground.
Alecsey [184]

Time taken by the water balloon to reach the bottom will be given as

h = \frac{1}{2} gt^2

here we know that

h = 18 m

g = 9.8 m/s^2

now by the above formula

18 = \frac{1}{2}*9.8* t^2

18 = 4.9 t^2

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now in the same time interval we can say the distance moved by it will be

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3 years ago
Un cubo de madera de densidad 0.780 g/cm³ mide 11.2 cm en un lado. Cuando se coloca en agua, ¿qué altura del bloque flotará sobr
Stolb23 [73]

Answer:

2.464 cm above the water surface

Explanation:

Recall that for the cube to float, means that the volume of water displaced weights the same as the weight of the block.

We calculate the weight of the block multiplying its density (0.78 gr/cm^3) times its volume (11.2^3  cm^3):

weight of the block = 0.78 * 11.2^3  gr

Now the displaced water will have a volume equal to the base of the cube (11.2 cm^2) times the part of the cube (x) that is under water. Recall as well that the density of water is 1 gr/cm^3.

So the weight of the volume of water displaced is:

weight of water = 1 * 11.2^2 * x

we make both weight expressions equal each other for the floating requirement:

0.78 * 11.2^3 = 11.2^2 * x

then x = 0.78 * 11.2 cm = 8.736 cm

This "x" is the portion of the cube under water. Then to estimate what is left of the cube above water, we subtract it from the cube's height (11.2 cm) as follows:

11.2 cm - 8.736 cm = 2.464 cm

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