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Andre45 [30]
2 years ago
10

PLEASE HELP!!!! ): PLEASE!!!

Physics
1 answer:
amid [387]2 years ago
6 0

Answer:

Because the person is changing direction

Explanation:

The acceleration of an object is defined as the rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

where

\Delta v is the change in velocity

\Delta t is the change in time

We must keep in mind that velocity is a vector, consisting of a speed and a direction. Therefore, a change in velocity means:

- either a change in the speed of the object, or

- a change in its direction

In this problem, the person is running around the track with a constant speed. However, his velocity is constantly changing (because the track is circular), this means that the change in velocity is not zero, and so there is a non-zero acceleration.

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The magnitude of two forces, which when acting at right angle produce resultant force of VlOkg and when acting at 60° produce resultant of Vl3 kg. These forces are D. gravitational force of attraction towards the centre of the earth. A sample of metal weighs 219 gms in air, 180 gms in water, 120 gms in an <em>unknown fluid</em>.

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2 years ago
How many electrons are in 204 C of charge?
zubka84 [21]

Answer:

The mass number 204 – 82 protons = 122 neutrons

Explanation:

Hope this helps!

5 0
2 years ago
What type of energy is formed when an object encounters friction?​
kiruha [24]

Answer:

thermal energy

Friction does negative work and removes some of the energy the person expends and converts it to thermal energy. The net work equals the sum of the work done by each individual force. The forces acting on the package are gravity, the normal force, the force of friction, and the applied force.

Explanation:

6 0
3 years ago
Read 2 more answers
Assume that you have a rectangular tank with its top at ground level. The length and width of the top are 14 feet and 7 feet, re
ch4aika [34]

To solve this problem we will use the work theorem, for which we have that the Force applied on the object multiplied by the distance traveled by it, is equivalent to the total work. From the measurements obtained we have that the width and the top are 14ft and 7ft respectively. In turn, the bottom of the tank is 15ft. Although the weight of the liquid is not given we will assume this value of 62 lb / ft ^ 3 (Whose variable will remain modifiable until the end of the equations subsequently presented to facilitate the change of this, in case be different). Now the general expression for the integral of work would be given as

W = \gamma A * \int_0^15 dy

Basically under this expression we are making it difficult for the weight of the liquid multiplied by the area (Top and widht) under the integral of the liquid path to be equivalent to the total work done, then replacing

W = (62)(14*7)\int^{15}_0 (15-y)dy

W = (14*7*62)\big [15y-\frac{y^2}{2}\big ]^{15}_0

W = (14*7*62)[15(15)-\frac{(15)^2}{2}]

W = 683550ft-lbs

Therefore the total work in the system is 683550ft-lbs

6 0
3 years ago
Q1. Tractors are often used on sloping fields, so stability is important in their design. On the diagram, the center of the X ma
Vesna [10]

Answer:

a) The tractor has not toppled over because the the center of mass is acting in between the wheels

b) The features which affect its stability are;

1) The location of the center of gravity of the tractor close to the ground

2) The increased spacing between the left and the right wheels of the tractor

Q2. a) The center of mass wheel act in the region to the right away the wheel span (space in between the wheel) which creates a clockwise effect to, topple the buses over

b) It raises the bus's center of mass higher

c) To raise the center of mass to its highest practical level

Q3. At the bottom middle location within the tractor

Explanation:

a) The tractor has not toppled over because the vertical line from the center of gravity to the ground is still in between the wheel base such that since the tractor will topple over by turning clockwise about the right tire due to its weight, the weight of the tractor is currently acting in the anticlockwise direction to the right end tire of the tractor keeping the tractor's tires in good contact with the ground

b) The features which affect its stability are;

1) The location of the center of gravity of the tractor close to the ground

2) The increased spacing between the left and the right wheels of the tractor

Q2. a) When either of the buses are tilted further, the mass of the buses is acting on the tires and in their tilted condition, the mass is acting mainly on the right tire, whereby as the vertical line from the center of mass to the ground is in between the wheel bases the mass of the buses still serve s the restoring force to keep the bus on ground by providing anticlockwise moment where clockwise lotion is required for the bus to topple over

If the buses are tilted further, the vertical line from the center of mass will cross to the other side of the right tire such that the mass now provides clockwise moment turning the buses clockwise and since there are no opposing anticlockwise moment to balance that of the now clockwise moment of the buses it will continue to turn clockwise with the result that they eventually  topple over

b) When the upper deck is full of passengers, there will be an appreciable proportion of the total mass of the bus in the upper deck such that the level of the center of mass will be raised up higher

c) Sand bags are only put upstairs because by allowing for the disproportionate distribution of load such that the majority of the load of the bus is concentrated upstairs, the center of mass will be at its maximum height allowing the bus to be tested for stability in the worst case scenario

Therefore, the sands are only put upstairs to raise the center of mass

Q3. Being that the tractor is being used on a rough ground, the safest position will be at the lowest possible location at the middle of both the front and rear wheels and the left and right tires.

5 0
3 years ago
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