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4 years ago

What is an equation of the line that passes through the point (-6,-4)(−6,−4) and is parallel to the line x+6y=12x+6y=12?

Mathematics

1 answer:

masya89 [10]4 years ago

4 0

Answer:

x + 6y + 30 = 0

Step-by-step explanation:

x + 6y = 12

6y = -x + 12

y = -⅙x + 2

Slope: -⅙

y - (-4) = -⅙(x - (-6))

y + 4 = -⅙(x + 6)

-6y - 24 = x + 6

x + 6y + 30 = 0

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