How many grams are in 5.2 grams of K
2 answers:
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Answer:
See attached => LeChatelier's Principle
Explanation:
LeChatelier's Principle => If a stress is applied to a chemical reaction, the reaction chemistry will shift away from the applied stress and establish a new equilibrium having new concentration values different from the original concentration values.
There are three (3) principle stress factors that will cause disturb a chemical reaction and cause it to shift to establish a new equilibrium. These are ...
=> concentration effects,
=> temperature effects, and
=> pressure-volume effects.
The attached notes explain in general terms how to evaluate a chemical reaction under an applied stress factor and determine direction of shift to establish a new equilibrium stability. Compare and apply to the worksheet problems.
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Answers to worksheet (compare to attached notes)
1a. => increasing wt to product side => tilts right => shifts left
1b. => removing wt from reactant side => tilts right => shifts left,
1c. => increasing wt to product side => tilts right => shifts left
2a. => tilts left (excess wt from Hg), shifts right,
2b. => Increase pressure shifts toward lower molar gas volume side (right) Note: apply only to gas phase substances, Hg is in liquid phase.
3a. exothermic rxn => cooling => tilts left, rxn shifts right
3b. endothermic rxn => cooling => tilts right, rxn shifts left
3c. exothermic rxn => cooling => tilts left, rxn shifts right
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Answer:
Explanation:
Given that:
The distillation is carried out at a pressure of 1 atm
The feed harbors 25% mole of methanol (z)
The total moles of feed is usually 100 moles
In the system, we have both methanol and water
Using the total mole balance for the distillation column.
Fz = Lx + Vy
where;
F = amount of feed
z = mole fraction of ethanol (in feed)
L = amount of liquid product out of the column
V = amount of vapor product out of the column
x = mole fraction of methanol out of the liquid
y = mole fraction of methanol out of the vapor.
SO;
(a)
If all the feed is vaporized, then the vapor will likely have the same composition as the feed.
(b)
If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.
(c)
If 1/3 of the feed is vaporized; then 2/3 of the feed is at the bottom.
The balance equation would be:
Replacing z = 0.25; we have:
0.75 = 2x + y
(d)
If 2/3 of the feed is vaporized;
Then:
replacing z = 0.25
0.75 = x + 2y