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Vanyuwa [196]
3 years ago
10

Please work out all the problems on this page, no links, no i don't knows please do not take advantage of me or my points please

actually answer these questions

Chemistry
2 answers:
Alexxandr [17]3 years ago
4 0

Answer:

Explanation:

SOLID-LIQUID-GAS

dimaraw [331]3 years ago
3 0
Solid-liquid-gas I’m pretty sure!((:
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Sodium thiosulfate, Na 2S 2O 3, is used as a "fixer" in black and white photography. Identify the reducing agent in the reaction
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Answer: Reducing agent in the given reaction is S_{2}O^{2-}_{3}.

Explanation:

A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.

In the given reaction, oxidation state of sulfur in S_{2}O^{2-}_{3} is +2 and I_{2}(aq) has 0 oxidation state.

In S_{4}O^{2-}_{6}(aq) oxidation state of S is 2.5 and in 2I^{-}(aq) oxidation state of I is -1.

Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.

Thus, we can conclude that reducing agent in the given reaction is S_{2}O^{2-}_{3}.

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