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nadezda [96]
3 years ago
15

What is a predicted outcome of a severe homeostatic disruption?​?

Biology
1 answer:
Kazeer [188]3 years ago
5 0
The predicted outcome is death
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Select the appropriate word(s) to complete the sentence.
kicyunya [14]

Seedless plants genetically alternate between generations.

<h3>What is the reproduction cycle of seedless plants like?</h3>

All seedless vascular plants have very similar life cycles. As in bryophytes, their life cycle has two alternating generations:

  • the gametophyte
  • and the sporophyte.
  • The sporophyte is always the dominant and free-living generation.

With this information, we can conclude that seedless plants genetically alternate between generations.

Learn more about Seedless plants in brainly.com/question/10715162

#SPJ1

8 0
2 years ago
Please help me with this question:)
lesantik [10]
Look it up on google , i had this same question and google helped me. i can’t remember the answer or i’d tell u
7 0
3 years ago
Which of the following is NOT a requirement for Hardy-Weinberg equilibrium?
aev [14]

Answer:

D. Small population size

Explanation:

Hardy-Weinberg equilibrium requires the presence of a large randomly mating population. Small population size makes the population more likely to deviate from the Hardy-Weinberg equilibrium due to sampling error or chance events occurring during the genetic drift. Large population size ensures that the population maintains the constant allele frequencies over generations, that is the Hardy-Weinberg equilibrium.

6 0
3 years ago
Plant and animal cells both have
aev [14]

Answer:

A nucleus, mitochondria, endoplasmic reticulum, golgi apparatus, and lysosomes.

Explanation:

8 0
3 years ago
Read 2 more answers
A geneticist is studying two traits in the fruit fly - eye color and wing shape. They perform a dihybrid cross. If the genes for
Len [333]

Answer:

3/16

Explanation:

<u>According to Mendel's law of independent assortment of genes, when a dihybrid cross involves two genes that assort independently and one of the parents is dominant for the two genes and the other is recessive, the phenotypic ratio of the offspring at F2 would be 9:3:3:1</u>. The proportion of the offspring with the dominant parental traits would be 9/16, those with the recessive parental traits would be 1/16, while those with mixed traits would be 3/16 each.

Assuming the eye color is represented by E and the wing shape is represented by W. At F2

     EeWw    x    EeWw

E_W_ - 9/16 (dominant for both eye color and wing shape)

E_ww - 3/16 (dominant for eye color and recessive for wing shape)

eeW_ - 3/16 (recessive for eye color and dominant for wing shape)

eeww - 1/16 (recessive for both eye color and wing shape)

<em>Hence, the proportion of the offspring with dominant phenotype for eye color and recessive phenotype for wing shape would be </em><em>3/16.</em>

3 0
3 years ago
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