It all depends on how big the boxes are but i would say about 5 or 6 boxes if they are big boxes
Answer:
Step-by-step explanation:
Put these numbers into their prime factors.
18: 2 * 3 * 3
27: 3 * 3 * 3
12: 2 * 2 * 3
The LCM must have
two 2s
Three 3s
That's it
2*2 * 3 * 3 * 3
LCM = 108
648 might be a multiple of the three, but it's not the smallest one.
108 = 27 * 4
108 = 18 * 6
108 = 12 * 9
Answer:
2 1/8
Step-by-step explanation:
7/8 is the same as 0.875 and therefore you need 0.125 also known as 1/8 to make it a whole number. When you add it to the already existing whole 2 you get three. Subtract three from five to make two which is what you need to add on top to finally get 5.
Answer:
A=-3/2
B=3
c=3/2
a=-2
Step-by-step explanation:
Knowing that for 
, 
when t<0 and using the definition of charge
The first term corresponds to q(0), the charge accumulated before t=0, in this case it luckily gives zero so we don't have to worry about it.
Let's proceed and integrate 
then when t>0
![i(t)=3\int_0^t \left[ \int_0^tdt'-\inte_0^t e^{-2t'}dt' \right]dt'=3\left[ t+\frac{1}{2}\left( e^{-2t}-1 \right) \right]=3t+\frac{3}{2}e^{-2t}-\frac{3}{2}\,\, C](https://tex.z-dn.net/?f=i%28t%29%3D3%5Cint_0%5Et%20%5Cleft%5B%20%5Cint_0%5Etdt%27-%5Cinte_0%5Et%20e%5E%7B-2t%27%7Ddt%27%20%5Cright%5Ddt%27%3D3%5Cleft%5B%20t%2B%5Cfrac%7B1%7D%7B2%7D%5Cleft%28%20e%5E%7B-2t%7D-1%20%5Cright%29%20%5Cright%5D%3D3t%2B%5Cfrac%7B3%7D%7B2%7De%5E%7B-2t%7D-%5Cfrac%7B3%7D%7B2%7D%5C%2C%5C%2C%20C)
It is clear that:
A=-3/2
B=3
c=3/2
a=-2
