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Fudgin [204]
3 years ago
8

What happens when an acid is added to pure water?

Chemistry
1 answer:
aliya0001 [1]3 years ago
8 0

Answer:

It will change it's PH level and will lessen the concentration of ions in the solution.

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4: The shikimate pathway is critically important and found in plants. Discuss reasons why this pathway is so important and even
Alecsey [184]

Answer:

Explanation:

For the growth and flourishing of animals Aromatic amino acids are very important, but because of lack of shikimate these amino acids are not synthesized in animals pathway.But this pathway is found in both plants and micro organisms and they have the ability to produce these amino acids as well as some secondary metabolites required in animals.

There are different role played by this pathway in organisms such as;

1) It serve as a source of Tryptophan and phenylalanie which are important aromatic amino acid.

2)Neuroactive substances such as serotonin,epinephrine are biosynthesized as result of the product from the pathway.

3)Alkaloids that's found in plants as well as antibiotics possessed by microbes, which are essential therapeutical in animals are secondary metabolites that is biosynthesized as a result of the activities of this product of this pathway.

4)Shikimate is useful in the synthesizing of 6-Fluoroshikimic acid.

5) The shikimate pathway is important for the synthesis of a plethora of aromatic compounds in both plants and bacteria as well as fungi.

4 0
3 years ago
Complete the chart. (Remember to enter a "0" if necessary.)
antoniya [11.8K]
Just remember how many electrons can each sublevel hold.

S=2
P=6
D=10

Since we have 10 for atomic number, we can assume we have 10 electrons

1S2
2S2
2P6
The rest have zero because we already have 10 (2+2+6=10)
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Consider the reaction between reactants s and o2: 2s(s)+3o2(g)→2so3(g)if a reaction vessel initially contains 7 mols and 9 mol o
nadya68 [22]

Answer: -

1 mol

Explanation: -

Number of moles of Sulphur S = 7

Number of moles of O2 = 9

The balanced chemical equation for the reaction is

2S (s)+3 O2 (g)→2SO3(g)

From the above reaction we can see that

3 mol of O2 react with 2 mol of S

9 mol of O2 will react with \frac{2 mol S x 9 mol O2}{3 mol O2}

= 6 mol of S

Unreacted S = 7 - = 1 mol.

If a reaction vessel initially contains 7 mol S and 9 mol O2

1 mole of s will be in the reaction vessel once the reactants have reacted as much as possible

6 0
3 years ago
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