Explanation:
It is known that density is the amount of mass present in liter of solution or substance.
Mathematically, Density = ![\frac{mass}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D)
It is given that volume is 3.25 L and mass is
. Hence, calculate the density of glycerol as follows.
Density = ![\frac{mass}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D)
= ![\frac{4.10 \times 10^{3} g}{3.25 L}](https://tex.z-dn.net/?f=%5Cfrac%7B4.10%20%5Ctimes%2010%5E%7B3%7D%20g%7D%7B3.25%20L%7D)
= ![1.26 \times 10^{3} g/L](https://tex.z-dn.net/?f=1.26%20%5Ctimes%2010%5E%7B3%7D%20g%2FL)
As, 1 L = 1000
.
So, ![1.26 \times 10^{3} g/L \times \frac{1000 cm^{3}}{1 L}](https://tex.z-dn.net/?f=1.26%20%5Ctimes%2010%5E%7B3%7D%20g%2FL%20%5Ctimes%20%5Cfrac%7B1000%20cm%5E%7B3%7D%7D%7B1%20L%7D)
=
Thus, we can conclude that the density of glycerol is
.
Answer:
k = 6.31 x 10⁻³ min⁻¹
Explanation:
The equation required to solve this question is:
k = 0693 / t half-life
This equation is derived from the the equation from the radioctive first order reactions:
ln At/A₀ = -kt
where At is the number of isoopes after a time t , and A₀ is the number of of isotopes initially. The half-life is when the number of isotopes has decayed by a half, so
ln(1/2) = -kt half-life
-0.693 = - k t half-life
t half-life = 109.8 min
⇒ k = 0.693 / t half-life = 0.693 / 109.8 min = 6.31 x 10⁻³ min⁻¹
Answer:
name : ethane
number of carbon atoms:2
formula: C2H6
Name: propane
Number of carbon atoms : 3
Formula: C3H8
Explanation:
Answer: POH=8
Explanation:PH = -log( H+concentration)
PH = 6
POH = 14 - PH = 8
Answer: difference in Vander Waals forces
Explanation:
The intermolecular force of attraction between the molecules in chlorine is WEAKER than that of Bromine.
This force is known as VANDER WAALS forces. And it DECREASES down the group; so Chlorine which is placed higher is a GAS, while Bromine placed lower in Group 7 is a LIQUID.