Answer:
i have no idea.
Step-by-step explanation:
We want to find the value that makes

To find it we must look at the standard normal table, using the complementary cumulative table we find that

Then, using the z-score we can find the minimum score needed, remember that

Where
σ = standard deviation
μ = mean
And in our example, x = minimum score needed, therefore

Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.
Answer:
4.
f(x) = (x + 2)(x + 1)(x - 3) = x^3 - 7·x - 6
a = 0 ; b = -7 ; c = -6
5.
a = -3 ∧ b = -2 ∧ c = -3
Answer: 
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10
(f o g)(-3) = (f(g(-3))
Because g is on the inside, we carry out g first.
g(x) = x^2 - 3
Substitute -3 in for x.
g(-3) = (-3)^2 - 3 = 9 - 3 = 6
g(-3) = 6
Next, carry out f on the result of g(-3)
f(6) = 2(6) - 1
= 12 - 1
= 11
So the answer is 11.