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4 years ago

Change .00025 to scientific notation

1 answer:

3 0

After you realize that
0.00025 = 2.5·10^-4
= 250·10^-6 or 250 μ
= 250,000·10^-9 or 250,000 n
then it becomes a matter of semantics. Both A and D are correct representations, so choice B is incorrect.

Choice C present a dilemma. If you say it is correct, then there are 3 correct choices (A, C, D), not two, so C is incorrect.

If you say it is incorrect, then there are two correct answers (A, D), making choice C correct.

I'd probably choose C and try to avoid the argument with my teacher.

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Alenkasestr [34]

Answer:

$x\geq 3$

Step-by-step explanation:

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3 years ago

Combine the like terms to create an equivalent expression.<br><br> 7k-k+19

Harlamova29_29 [7]

Answer:

6k +19

Step-by-step explanation:

7k-k+19

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3 years ago

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sdas [7]

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3 years ago

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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

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3 years ago

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