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nataly862011 [7]
3 years ago
12

Find the position function of a particle moving along a coordinate line that satisfies the given conditions. 2sint-cost

Mathematics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

the position of a particle moving at a coordinate say(y) will satisfy the given conditions t=0 (say) if y=2sint-cost

Step-by-step explanation:

Clearly by the above we can see that if y=2sint-cost at t=0, then y=-1 because at t=0 sint vanishes and leaves us with only cost and at t=0 cos0=1

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xenn [34]

The volume of the prism given its dimensions is equal to 160 cubic units.

<h3>What is the volume of the prism?</h3>

The given prism is made up of two prisms. The volume of the prism is the volume of the two shapes.

  • One of the prisms have the dimensions: 4 x 4 x 5.

Volume = 80

  • The other prism has the dimensions: 8 x 2 x 5.

Volume = 80

Volume of the prism = 80 x 2 = 160 cubic units.

To learn more about rectangular prisms, please check: brainly.com/question/8890358

8 0
2 years ago
Which of the following choices
Lapatulllka [165]

Answer:

Denote AH as height of triangle ABC, with H lies on BC.

Applying sine theorem:

AH/AC = sin 60

=> AH = AC x sin 60 = 47 x sqrt(3)/2 = 40.7

=> Area of triangle ABC is calculated by:

A = AH x BC x (1/2) = 40.7 x 30 x (1/2) = 610.5 = ~611

=> Option C is correct.

Hope this helps!

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3 0
3 years ago
Will someone please help me solve this !!
Cerrena [4.2K]

360=95+120+120+125+x+84+x

360=544+2x

-184=2x

x= -92

7 0
3 years ago
30 POINTS!
Alona [7]

Answer:

Area = 3,656.6 m²

Step-by-step explanation:

Area enclosed by the track is composed of two semicircles and a rectangle.

Area = area of two semicircles + area of rectangle

= 2(½*πr²) + L*W

Where,

radius of semicircle (r) = ½of 40 m = 20 m

Length of rectangle (L) = 60 m

Width of rectangle (W) = 40 m

Plug in the values

Area = 2(½*π*20²) + 60*40

Area = 400π + 2,400

Area = 3,656.6 m² (aooroximated to nearest tenth)

8 0
3 years ago
Read 2 more answers
Professor Goodheart has two exams, exam 1 and exam 2. The exam 1 weights 40% and the exam 2 weights 60% of the final grades. Put
garri49 [273]

Answer:

Imperfect substitutes

explanation:

The choices above are not perfect substitutes, meaning they can not be perfectly or directly replace the other. Imperfect substitutes are close substitutes but not perfect substitutes. Unlike perfect substitutes, imperfect substitutes satisfies same utility but has different characteristics and therefore not entirely substitutable. For example, while one may want to have the 40 marks too, he'd rather have 60 marks even if the criteria for a 60 mark score was increasingly hard.

8 0
3 years ago
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