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2 years ago

12

One of the effects of drug abuse is hallucination. What does this term mean

1 answer:

Oduvanchick [21]2 years ago

3 0

Explanation:

Hallucinogen, substance that produces psychological effects that tend to be associated with phenomena such as dreams or religious exaltation or with mental disorders such as schizophrenia.

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Consider the following reaction.

Ivan

Answer:

162 g Fe₂O₃

Explanation:

To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (C): 12.011 g/mol

2 Fe₂O₃(s) + 3 C(s) ---> 4 Fe(s) + 3 CO₂(g)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

18.3 g C 1 mole 2 moles Fe₂O₃ 159.684 g
-------------- x ---------------- x ------------------------- x ----------------- = 162 g Fe₂O₃
12.011 g 3 moles C 1 mole

5 0

1 year ago

Please help me with this question!!

mestny [16]

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$ $\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles$

$2Na+Cl_2\rightarrow 2NaCl$

According to stoichiometry :

1 mole of $Cl_2$ produce = 2 moles of $NaCl$

Thus 7.04 moles of $Cl_2$ will produce= $\frac{2}{1}\times 7.04=14.08moles$ of $NaCl$

Mass of $NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g$

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

3 0

2 years ago

Cevabı atar mısınız lütfen

yawa3891 [41]

I’m sorry I don’t understand if you can may you say it in English?

4 0

2 years ago

A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera

Grace [21]

Answer: The initial temperature of the iron was $515^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of iron = 360 g

$m_2$ = mass of water = 750 g

$T_{final}$ = final temperature = $46.7^0C$

$T_1$ = temperature of iron = ?

$T_2$ = temperature of water = $22.5^oC$

$c_1$ = specific heat of iron = $0.450J/g^0C$

$c_2$ = specific heat of water= $4.184J/g^0C$

Now put all the given values in equation (1), we get

$-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]$

$T_i=515^0C$

Therefore, the initial temperature of the iron was $515^0C$

4 0

2 years ago

As you move from row ______ to row ______ in the periodic table, the atomic radius of the elements DECREASES.

Margarita [4]

Answer:

7 to 1

Explanation:

As you move from row ----- to row ------ in the periodic table, the atomic radius of the elements DECREASES.?

And we have 7 rows in a periodic table, so the answer has to either 1 to 7 or 7 to 1

Theoretically,

Atomic size increase as we move from top to bottom as an extra shell gets added up with every period.

SO, the answer is, 7 to 1

6 0

2 years ago