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Gala2k [10]
3 years ago
15

The synthesis of dipropyl ether can be accomplished using 1-propanol. What reactants and conditions are necessary for this to oc

cur
Chemistry
1 answer:
satela [25.4K]3 years ago
3 0

Answer: Reactants==>2 molecules of propanol.

Condition for Reaction to occur==> Strong acid,e.g HCl and high temperature (140°C).

Explanation:

Dipropyl ether can be sythesized commonly in two ways;

(1). Williamson ether synthesis of dipropyl ether: this chemical reaction involves the reaction of alkyl halide(propyl halide) with conjugate base of propanol.

(2). Acid catalyzed ether synthesis of dipropyl ether: this is the reaction this question is talking about. A strong acid is used in the Chemical Reaction, and , it is reaction between two(2) molecules of propanol. This is done in the presence of strong acid such as HCl and high temperature (up to 140°C).

The Reactants are the two molecules of propanol. The condition necessary for the reaction to occur is that the temperature must be high(140-143°C) and it must be in the presence of a strong acid.

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A mixture containing nitrogen and hydrogen weighs 3.49 g and occupies a volume of 7.45 L at 305 K and 1.03 atm. Calculate the ma
-BARSIC- [3]

Answer:

Mass percent N₂ = 89%

Mass percent H₂ = 11%

Explanation:

First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:

  • 1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K
  • n = 0.307 mol

So now we know that

  • MolH₂ + MolN₂ = 0.307 mol

and

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g

So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:

Express MolH₂ in terms of MolN₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ = 0.307 - MolN₂

Replace that value in the second equation:

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
  • (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
  • 0.614 - 2MolN₂ + 28molN₂ = 3.49
  • 0.614 + 26MolN₂ = 3.49
  • MolN₂ = 0.111 mol

Now we calculate MolH₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ + 0.111 = 0.307
  • MolH₂ = 0.196 mol

Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:

  • N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂
  • H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂

Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%

Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%

5 0
3 years ago
How many moles of carbon (C) are there in 92.5 g of C?
aksik [14]

Answer:

c are there 93.5 of c yan siguro

8 0
2 years ago
Which of the following mixtures may be act as a buffer solution?
lions [1.4K]

Answer:

B) HF, NaF

Explanation:

  • A buffer solution is made up of a weak acid and its conjugate base.
  • In this case, HF is a weak acid and NaF is the conjugate base, therefore the mixture of HF,  and NaF would make a perfect buffer solution.
  • The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.
4 0
3 years ago
No links please. How many moles of methane (CH4) are in 7.31x10^25 molecules?
ad-work [718]

Answer:

molar mass of methane CH4

= C + 4 H  

= 12.0 + 4 x 1.008

= 12.0 +  4.032

= 16.042g/mol

7.31 x 10^25 molecules x             1 mole  CH4      = 121.43 moles

                                      6.02 x 10^23 CH4 molecules

121.43 moles CH4 are present.

Explanation:

not to certain if this is right or not.. but hope it helps!

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a person running a car parked in a driveway

Explanation:

A person running a car parked in a driveway is an example of translational kinetic energy.

Translational motion is the movement of body along a straight path.

Translational kinetic energy refers to the energy of a body moving along a straight path.

  • It is function of the mass and velocity of the moving body.
  • The motion of train on its track is an example of this form of energy
  • A fired bullet, falling object all experience translational kinetic energy.

learn more:

Translational kinetic energy brainly.com/question/9924094

#learnwithBrainly

3 0
3 years ago
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