Question

Do anybody know the anwer to this question? 1/64=16^2x

Answer 1

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Question
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$\dfrac{1}{64} = 16^2^x$

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Rewrite 64 as 2⁶ and 16 as 2⁴
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$\dfrac{1}{2^6} = (2^4)^2^x$

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Convert the denominator to numerator and evaluate the power
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$2^-^6 = 2^8^x$

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Since both are base 2, equate the power
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$-6 = 8x$

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Divide by 8 to find x
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$x = - \dfrac{6}{8}$

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Reduced Form
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$x = - \dfrac{3}{4}$

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$\bf Answer: \ = \ - \dfrac{3}{4}$
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