Find the slope of the line given below by finding the rise and run. Also show or explain why the slope can be found from any two
points that fall on the line.
1 answer:
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Given:
The vertices of a polygon QRST are T(-2, 3), Q(1, 5), R(3, -1) and S(0, 0).
To find:
The vertices for .
Solution:
The rule represents refection of polygon QRST across the x-axis.
If a figure is reflected across the x-axis, then
Using this rule, we get
Therefore, the vertices for are T'(-2, -3), Q'(1, -5), R'(3, 1) and S'(0, 0).
Answer:
However, that's the length of "c" and you're looking to drag it in. So,o you drag in 10^2+7^2=a^2.
Then, as shown by the first picture attatched, you can drag in the one with "c" and "a" with the five shown.
Step-by-step explanation:
To find "c" the diagonal, as explained, you need to use the theorem twice. You can first use it by finding "a", as you already have "b". To find a, you do 10^2+7^2=a^2, the hypotenuse.
100+49=149.
So, a is root 149.
a^2+b^2=c^2 so
149+25=174