Answer:
16.8ohms
Explanation:
According to ohm's law which states that the current passing through a metallic conductor at constant temperature is directly proportional to the potential difference across its ends.
Mathematically, V = IRt where;
V is the voltage across the circuit
I is the current
R is the effective resistance
For a series connected circuit, same current but different voltage flows through the resistors.
If the initial current in a circuit is 19.3A,
V = 19.3R... (1)
When additional resistance of 7.4-Ω is added and current drops to 13.4A, our voltage in the circuit becomes;
V = 13.4(7.4+R)... (2)
Note that the initial resistance is added to the additional resistance because they are connected in series.
Equating the two value of the voltages i.e equation 1 and 2 to get the resistance in the original circuit we will have;
19.3R = 13.4(7.4+R)
19.3R = 99.16+13.4R
19.3R-13.4R = 99.16
5.9R = 99.16
R= 99.16/5.9
R = 16.8ohms
The resistance in the original circuit will be 16.8ohms
<h2>The acceleration of car is 0.2 ms⁻²</h2>
Explanation:
When the car moves , the distance covered is calculated by the relation
S = u t +
a t²
In this question u = 0 , because car was at rest initially
Thus S =
a t²
here S is displacement and a is the acceleration of car
Therefore 360 =
a ( 60 )²
Because time taken is one minute or 60 seconds
Therefore a = ![\frac{360x2}{3600}](https://tex.z-dn.net/?f=%5Cfrac%7B360x2%7D%7B3600%7D)
or a = 0.2 m s⁻²
Answer:
(D) all of the above
Explanation:
All of the choices describe matter.
Answer:
0.62
Explanation:
A = Amplitude
f = Frequency = 1.85 Hz
= Coefficient of static
g = Acceleration due to gravity = 9.81 m/s²
Angular frequency
![\omega=2\pi f\\\Rightarrow \omega=2\pi\times 1.85](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%20f%5C%5C%5CRightarrow%20%5Comega%3D2%5Cpi%5Ctimes%201.85)
Maximum acceleration
![a_{max}=A\omega^2\\\Rightarrow a_{max}=0.045\times (2\pi\times 1.85)^2](https://tex.z-dn.net/?f=a_%7Bmax%7D%3DA%5Comega%5E2%5C%5C%5CRightarrow%20a_%7Bmax%7D%3D0.045%5Ctimes%20%282%5Cpi%5Ctimes%201.85%29%5E2)
![a_{max}=\mu g\\\Rightarrow \mu=\frac{a_{max}}{g}\\\Rightarrow \mu=\frac{0.045\times (2\pi\times 1.85)^2}{9.81}\\\Rightarrow \mu=0.62](https://tex.z-dn.net/?f=a_%7Bmax%7D%3D%5Cmu%20g%5C%5C%5CRightarrow%20%5Cmu%3D%5Cfrac%7Ba_%7Bmax%7D%7D%7Bg%7D%5C%5C%5CRightarrow%20%5Cmu%3D%5Cfrac%7B0.045%5Ctimes%20%282%5Cpi%5Ctimes%201.85%29%5E2%7D%7B9.81%7D%5C%5C%5CRightarrow%20%5Cmu%3D0.62)
Coefficient of static friction between penny and tabletop is 0.62
Answer: A
Explanation: If you drop an object in the absence of air resistance, it accelerates downward at 9.8 m/s2.