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Butoxors [25]
3 years ago
7

A 20-kg child running at 1.4 m/s jumps onto a playground merry-go-round that has mass 180 kg and radius 1.6m. She is moving tang

ent to the platform when she jumps and she lands right on the edge. What is the angular velocity of the child and the merry-go-round if the merry-go-round started from rest
Physics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

ωf = 0.16 rad/s

Explanation:

Moment of inertia of the child = mr² = 20(1.6²) = 51.2 kg•m²

Moment of Inertia of the MGR = ½mr² = ½(180)1.6² = 230.4 kg•m²

(ASSUMING it is a uniform disk)

Initial angular momentum of the child = Iω = I(v/r) = 51.2(1.4/1.6) = 44.8 kg•m²/s

Conservation of angular momentum

44.8 = (51.2 + 230.4)ωf

ωf = 0.15909090...

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The length of vector A is 93.8 meters and the length of Ay is 38.4 meters, then the length of A, must be
vaieri [72.5K]

Answer:

85.556metres

Explanation:

Using pythagorean theorem

C²=A²+B²

we have c as the hypotenuse vector A thus:

93.8²=A²+38.4²

93.8²-38.4²=A²

8794.44-1474.56=A²

7319.88=A²

A=85.556

3 0
3 years ago
A rocket initially at rest accelerates at a rate of 99. 0 meters/second2. Calculate the distance covered by the rocket if it att
creativ13 [48]

The rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s. Acceleration can be defined as the change in velocity.

<h3>What is acceleration?</h3>

Acceleration can be defined as the change in speed or the direction of the object.

From kinamatic equation:

D = v_{t} +\dfrac 12at^2

Where,

D - final velocity =  445 m/s

v_0 -  initial valocity = 0 m/s

a - acceleration = 99. 0 m/s²

t - time =  4. 50 s

Put the values in the formula,

D = 0\times  ( 4.5) + \dfrac12\times (99)(4.5)^2\\\\D = 1002 {\rm \ m}\\\\D = 1 \times  10^3\rm \ m

Therefore, the rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s.

Learn more about Acceleration :

brainly.com/question/2697545

7 0
3 years ago
If you are given the mass of an object in pounds, the time in seconds, and the distance in feet, what must you do before you can
Alexandra [31]

Answer: First you must convert pound in kilogram, and feet in meter

Explanation:

To calculate momentum we use .

p=m*V

mass-m

speed-V

distance and time are used to calculate velocity(speed)

You are given :

 mass- in pounds

for distance - in feet

before you do any calculation first you have to convert pounds in kilograms

and feet in meters.

5 0
3 years ago
You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc
FrozenT [24]

Answer:

The balloon hit the ground with velocity -15.34 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

burst when it hits the ground is 12 meters.

We consider that the 12 meters is the maximum height, so the velocity

at this height is zero.

To find the velocity when the balloon hits the ground lets use the rule

<em>v² = u² + 2gh</em>, where v is the final velocity, u is the initial velocity, g is

the acceleration of gravity and h is the height.

u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

v² = 0 + 2(9.8)(12)

v² = 235.2

<em>Take square root for both sides</em>

v = ± \sqrt{235.2}

The velocity is downward, then it's a negative value

Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

6 0
3 years ago
How an application of atmospheric device work?example siphon​
Vika [28.1K]

Answer:

A practical siphon, operating at typical atmospheric pressures and tube heights, works because gravity pulling down on the taller column of liquid leaves reduced pressure at the top of the siphon (formally, hydrostatic pressure when the liquid is not moving).

I hope it's helpful!

6 0
3 years ago
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