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3 years ago

What are the characteristics of a nebulae? (Select all that apply.)

Physics

1 answer:

erica [24]3 years ago

7 0

Answer:

B. contain hydrogen

C. clouds of gas and dust

E. needed to create a star

Explanation:

A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.

Some of the examples of stars are; Vega, Sun (closest to planet Earth), Antares, Betelgeus, Canopus, etc.

Stars are typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He). The chronological order in which the formation of a star occur are;

1. Gravity pulls gas and dust together to form dense cores.

2. A protostar forms as mass increases.

3. Nuclear fusion begins under high pressure.

Scientists have been able to understand and discover that, gravity pulled materials (low-density cloud of interstellar gas and dust known as a nebula) together forming the planetary bodies in our solar system.

A dark nebula can be defined as an interstellar cloud that is so dense as a result of high concentration of gas and dust and as such it obscures the visible wavelengths of light from stars behind it, thus appearing completely opaque (dark patch) in front of a bright emission nebula or in regions having plenty stars.

The characteristics of a nebulae are;

I. It contain hydrogen.

II. Clouds of gas and dust

III. It is needed to create a star.

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How much force is needed to push a 20kg at 0.2 m/s/s<br> A)10 N<br> B)20 N<br> C)4 N<br> D)40 N

ad-work [718]

Answer:

Explanation:

20x.2=4

4 0

2 years ago

Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t

Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

$g=\frac{GM}{R^2}=9.70 m/s^2$

where G is the gravitational constant

M is the Earth's mass

$R=6378km = 6.378 \cdot 10^6 m$ is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

$M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg$

The Earth's volume is (approximating the Earth to a perfect sphere)

$V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3$

So, the average density of the Earth is

$\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3$

4 0

4 years ago

Read 2 more answers

Calculate the electrical energy expended in a device across which the circuit voltage drops by 20.0 volts in moving a charge of

Inga [223]

Answer:

The answer is 80 Joules

Explanation:

Electrical energy = Q x V

Energy = 2 x 40

= 80

I just took the test and it was right :D

The correct answer is B.

I hope this helped! :D

6 0

4 years ago

Two identical ions are each missing two electrons, each ion has a charge of 2e. What is the magnitude of the force between the i

xz_007 [3.2K]

Answer:

|F| = 2.09 × 10⁻⁸ assuming that the two ions are point charges.

Explanation:

What's the charge on each ion?

The symbol $e$ here stands for fundamental charge. Each electron carries a negative fundamental charge of -e. Each proton carry a positive fundamental charge of +e.

Molecules and atoms are neutral. They contain an equal number of electrons and protons. Remove one electron from a molecule or atom, and that particle will end up with more protons (which are positive) than electrons. That particle will carry a positive charge of +e become an ion (a cation to be precise.) Remove another electron and the ion will carry a charge of +2e.

For each ion $q = +2 \;e = 2\times 1.60\times 10^{-19}\;\text{C} = 3.2\times 10^{-19}\;\text{C}$ .

What's the size of the electrostatic force between the two ions?

Consider Coulomb's Law for the electrostatic force $F$ between two point charges:

$\displaystyle F = -\frac{k\cdot q_1\cdot q_2}{r^{2}}$ ,

where

$k$ is Coulomb's constant,
$q_1$ and $q_2$ are the charge on the two point charges, and
$r$ is the separation between the two charges.

Make sure that all values are in SI units. Assume that the two ions are small enough that they act like point charges:

$\displaystyle \begin{aligned}F &= -\frac{k\cdot q_1 \cdot q_2}{r^{2}}\\&=-\frac{8.99\times 10^{9}\cdot(3.2\times 10^{-19}) \cdot (3.2\times 10^{-19})}{(2.1\times 10^{-10})^{2}}\\ &= -2.09\times 10^{-8}\;\text{N}\end{aligned}$ .

The value of $F$ is negative, meaning that the two charges will repel each other because they are both positive. The question is asking for the magnitude of this force. Thus drop the sign in front of $F$ to obtain $2.09\times 10^{-8}\;\text{N}$ , which is the magnitude of $F$ .

5 0

3 years ago

The electric field is strongest where equipotential curves are:_______.A) closest togetherB) farthest apartC) most nearly straig

cluponka [151]

Answer:

A closest

Explanation:

This is because the electric field will be strongest or largestwhen the equipotential curves are closest together

We know that the field is

E= V/d

Where is distance and we see that d being the denominator will only make E bigger if it becomes smaller that is the curves closest

3 0

3 years ago