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oksano4ka [1.4K]
3 years ago
14

Number of electrons present in 3.6mg of NH₄⁺?​

Chemistry
1 answer:
nata0808 [166]3 years ago
4 0
0.0036g of NH4+ x 1mol of NH4+/18.04g of NH4+ x 6.02*10^23 electrons of NH4+/1mol of NH4+

= 1.20 x 10^20 electrons of NH4+
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