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Zolol [24]
3 years ago
13

What is the difference between a constellation and an “asterism”? Name at least one commonly known asterism.

Physics
1 answer:
marta [7]3 years ago
7 0
A "constellation" is the total, full, complete thing in the night sky ...
ALL of the stars that go together to make up the complete dog or
the queen or the fish or the bear, or whatever else the story of
that particular part of the sky involves.

An "asterism" is a small, easily recognized group of stars, that
can be spotted right away, although they're only a small part
of a constellation.

The Big Dipper, the Little Dipper, Orion's Belt, and the Great Square
are asterisms.  They're parts of the constellations of the Big Bear,
the Little Bear, Orion the Great and Mighty Hunter, and Pegasus,
respectively.
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Answer:

Aufbau diagram of sodium ion:

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A bat emits a sound at a frequency of 30.0 kHz as it approaches a wall. The bat detects a beat frequency of 700 Hz. The speed of
ASHA 777 [7]

Answer:

3.948m/s

Explanation:

To solve this we need to apply Doppler effect theory

So

To find the frequency received by insect will be gotten when the Source and observer both are moving in same direction which is given by

f1 = f0 x (V - Vo)/(V - Vs)

f0 = 30.0 kHz

V = 344 m/s

Vs will now be the speed of the bat and

Vo will be the speed of the object which is = 0 m/s

So substituting we have

f1 = 30 x 10^3 x (344- 0)/(344- Vs)

Next to find the frequency reflected by wall we use

f2 = f1 x (V + Vs)/(V + Vo)

So substituting the value of f1 calculated above we have

f2 = 30 x 10^3 x (344 + Vs) x (344 - 0)/[(344 - Vs) x (344 + 0)]

f2 = 30 x 10^3 x (344 + Vs)/(344- Vs)

But the beat frequency detected by bat is 700 Hz,

So we say

f2 - f0 = 700 Hz

30 x 10^3 x (344+ Vs)/(344 - Vs) - 30x 10^3 = 700

(344 + Vs)/(344 - Vs) = 1 + 700/30000 = 1.023

344 + Vs = 344 x 1.023 - Vs x 1.0233

Vs = 344 x ( 1.023 - 1)/(1 + 1.023)

So finally

Vs = Speed of source that is the bat is = 3.949m/s

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Please select the word from the list that best fits the definition
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Answer:

wavelength

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I think that's the answer

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If the amount of matter of something is increased
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Answer:

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