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padilas [110]
2 years ago
7

The period of a 400 hertz sound wave is ___ second

Physics
2 answers:
amm18122 years ago
5 0
0.0025 per second your welcome
Oksi-84 [34.3K]2 years ago
3 0

Answer:

0.0025 sec

Explanation:

Period = 1 / frequency = 1/400 = 0.0025 sec

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25 points! Please someone help me, this seems like a pretty easy question but I can’t seem to get it right, please list the give
elixir [45]

Answer:

1 my brother say that

Explanation:

i know my brother said it

4 0
3 years ago
The value of the surface area of the cylinder is equal to the value of the volume of the cylinder. Find the value of x.
max2010maxim [7]

The volume of a cylinder is given by the formula v=pi r^2h, where r is the radius of the cylinder and h is the height.

<h3>What Does a Cylinder's Surface Area Look Like?</h3>

The overall area or region that the surface of a cylinder covers is referred to as its surface area. A cylinder's total surface area includes both the area of the curved surface and the area of the two flat surfaces because there are two flat surfaces and one curved surface. A cylinder's surface area is measured in square units like m2, in2, cm2, yd2, etc.

<h3>What is the cylinder's total surface area?</h3>

The sum of the curved surface areas makes up the cylinder's overall surface area.

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brainly.com/question/22074027

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5 0
1 year ago
What will happen two temperatures if you increase particle motion
nalin [4]

If the temperature is increased the particles gain more kinetic energy or vibrate faster. This means that they move faster and take more space.

8 0
3 years ago
Luis and Aisha conducted an experiment. They exerted different forces on four objects. Their results are shown in the table.
lesya692 [45]

Answer:

Object 3 has greatest acceleration.

Explanation:

Objects               Mass                                Force

1                            10 kg                               4 N              

2                           100 grams                       20 N

3                            10 grams                         4 N

4                             1 kg                                 20 N

Acceleration of object 1,

a_1=\dfrac{F_1}{m_1}\\\\a_1=\dfrac{4}{10}\\\\a_1=0.4\ m/s^2

Acceleration of object 2,

a_2=\dfrac{F_2}{m_2}\\\\a_2=\dfrac{20}{0.1}\\\\a_2=200\ m/s^2

Acceleration of object 3,

a_3=\dfrac{F_3}{m_3}\\\\a_3=\dfrac{4}{0.01}\\\\a_3=400\ m/s^2

Acceleration of object 4,

a_4=\dfrac{F_4}{m_4}\\\\a_4=\dfrac{20}{1}\\\\a_3=20\ m/s^2

It is clear that the acceleration of object 3 is 400\ m/s^2 and it is greatest of all. So, the correct option is (3).

4 0
3 years ago
Read 2 more answers
You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther
Travka [436]

Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K

Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

T2 = T1 * (P2/P1)

T2 = (100 + 273) * (500 / 294)

T2 = 373 * (500 / 294)

T2 = 373 * 1.7

T2 = 634 K

T2 = 634 K - 273 K = 361° C

5 0
3 years ago
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