<h3>
Answer:</h3>
69.918 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of iron oxide as 100 g
We are supposed to determine the maximum theoretical yield of Iron from the blast furnace;
- The equation for the reaction in the blast furnace that extracts Iron from iron oxide is given by;
Fe₂O₃ + 3CO → 2Fe + 3CO₂
- We can first determine moles of Iron oxide;
Moles = Mass ÷ Molar mass
Molar mass of Fe₂O₃ = 159.69 g/mol
Therefore;
Moles of Fe₂O₃ = 100 g ÷ 159.69 g/mol
= 0.626 moles
- Then we determine moles of Iron produced
From the equation;
1 mole of Fe₂O₃ reacts to produce 2 moles of Fe
Therefore;
Moles of Fe = Moles of Fe₂O₃ × 2
= 0.626 moles × 2
= 1.252 moles
- Maximum theoretical mass of Iron that can be obtained
Mass = Moles × molar mass
Molar mass of Fe = 55.845 g/mol
Therefore;
Mass of Fe = 1.252 moles × 55.845 g/mol
= 69.918 g
Therefore, the maximum theoretical mass of Iron metal obtained is 69.918 g
